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notka56 [123]
3 years ago
6

Hurry in need of help! Please

Mathematics
1 answer:
Bas_tet [7]3 years ago
3 0

\\ \sf\dashrightarrow \dfrac{x+20}{2}=3x

\\ \sf\dashrightarrow x+20=2(3x)

\\ \sf\dashrightarrow x+20=6x

\\ \sf\dashrightarrow 20=6x-x

\\ \sf\dashrightarrow 5x=20

\\ \sf\dashrightarrow x=\dfrac{20}{5}

\\ \sf\dashrightarrow x=4

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Option D: x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7 is

<h3>What is binomial theorem?</h3>

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<h3>How to use binomial theorem for given expression?</h3>

Taking a = x, and b =2y, we have n = 7, thus:

(x+2y)^7 = \: ^7C_0x^0(2y)^7 + \: ^7C_1x^1(2y)^6 + \: ^7C_2x^2(2y)^5 + \: ^7C_3x^3(2y)^4 + \:^7C_4x^4(2y)^3 + \:^7C_5x^5(2y)^2 + \:^7C_6x^6y^1 + \: ^7C_0x^7y^0\\\\&#10;(x+2y)^7 = 128y^7 + 448xy^6 + 672x^2y^5 + 560x^3y^4 + 280x^4y^3 + 84x^5y^2 + 14x^6y + x^7\\\\&#10;(x+2y)^7 = x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7

Thus, Option D: x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7 is correct.

Learn more about binomial theorem here:

brainly.com/question/86555

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2 years ago
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Read 2 more answers
A pharmacist has an 18% alcohol solution and a 40% alcohol solution. How much of each should he mix together to make 10 liters o
ladessa [460]
X = amount of the 18% solution

y = amount of the 40% solution

we know the 18% solution has only 18% of alcohol, the rest is maybe water or something, now, how many liters is 18%?  well, 18% of anything is just (18/100) * anything, so, 18% of x is just (18/100) *x or 0.18x, and that's how many liters are there.

likewise, how many liters are there in the 40% solution?  well, (40/100) * y, or 0.4y, that many.

we know the mixture has to yield 10 liters at 20% alcohol, how many liters of only alcohol is that?  well, (20/100) * 10, or 2 liters.

\bf \begin{array}{lccclll}&#10;&\stackrel{liters}{amount}&\stackrel{alcohol~\%}{quantity}&\stackrel{liters}{alcohol}\\&#10;&------&------&------\\&#10;\textit{18\% solution}&x&0.18&0.18x\\&#10;\textit{40\% solution}&y&0.40&0.4y\\&#10;------&------&------&------\\&#10;mixture&10&0.20&2&#10;\end{array}

\bf \begin{cases}&#10;x+y=10\implies \boxed{y}=10-x\\&#10;0.18x+0.4y=2\\&#10;----------\\&#10;0.18x+0.4\left( \boxed{10-x} \right)=2&#10;\end{cases}&#10;\\\\\\&#10;0.18x-0.4x+4=2\implies -0.22x=-2&#10;\\\\\\&#10;x=\cfrac{-2}{-0.22}\implies x=\cfrac{100}{11}\implies x=9\frac{1}{11}

how much of the 40% solution?  well y = 10 - x
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