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Vlad [161]
3 years ago
12

Scale factor for a model is 15cm. Actual =55.5m. model. =25.25. What is the meter

Mathematics
1 answer:
Rasek [7]3 years ago
3 0
We calculate for the actual length of the thing in the model that measures 25.25 by multiplying this value by the scale factor. That is,
                             (25.25 cm) x (55.5 m / 15 cm) = 93.425 m
Therefore, the real dimension of the object is approximately 93.43 m. 
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The inner circle circumference is 52 ft. the distance between the inner and the outer circle is 8ft. By how many ft is the outer
rjkz [21]

Answer:

The outer circle is 16 feet larger than the inner circle (68 - 52).

Step-by-step explanation:

Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:

The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).

This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).

8 0
2 years ago
In an art class 40% of the students use watercolors for pain 10 students in the art class use watercolors how many students were
yarga [219]

10=0.4%*n

100 = 4n

n=100/4

n= 25 students


3 0
3 years ago
30 POINTS AVAILABLE
kherson [118]

Answer:

\large\boxed{(x-2)^2+(y-1)^2=34}

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

Substitute:

h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points (2, 1) and (5, -4):

r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}

Finally we have:

(x-2)^2+(y-1)^2=(\sqrt{34})^2

3 0
3 years ago
7/22 rounded to the nearest thousandth
Artyom0805 [142]

Answer:

0.318

Step-by-step explanation:

4 0
3 years ago
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S_A_V [24]
Total bill-$67.95
each friends owes about $16.99
6 0
3 years ago
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