Hello,
P(x)=x^3+2x²-23x-60
P(-4)=(-4)^3+2*(-4)²-23*(-4)-60=0
P(-3)=(-3)^4+2*(-3)²-23*(-3)-60=0
P(5)=5^3+2*5²-23*5-60=0
Zeros are -4,-3,5
Answer:
if there is 40 passengers and 4 passengers per car there are 10 cars
fog(x+2) = f(g(x+2) = f ( x+2+7)
= f(x+9)
= x+9- 4
(f g)(x + 2) = x+5
Answer:
40
Step-by-step explanation:
