The length of the side joining points (-3, -1) and (1, 3) is given by
![l= \sqrt{(1+3)^2+(3+1)^2} \\ \\ = \sqrt{4^2+4^2} = \sqrt{16+16} \\ \\ = \sqrt{32}](https://tex.z-dn.net/?f=l%3D%20%5Csqrt%7B%281%2B3%29%5E2%2B%283%2B1%29%5E2%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%5Csqrt%7B4%5E2%2B4%5E2%7D%20%3D%20%5Csqrt%7B16%2B16%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%5Csqrt%7B32%7D%20)
The length of the side joining points (1, 3) and (3, 1) is given by
![w= \sqrt{(3-1)^2+(1-3)^2} \\ \\ = \sqrt{2^2+(-2)^2} = \sqrt{4+4} \\ \\ = \sqrt{8}](https://tex.z-dn.net/?f=w%3D%20%5Csqrt%7B%283-1%29%5E2%2B%281-3%29%5E2%7D%20%5C%5C%20%5C%5C%20%3D%20%5Csqrt%7B2%5E2%2B%28-2%29%5E2%7D%20%3D%20%5Csqrt%7B4%2B4%7D%20%5C%5C%20%5C%5C%20%3D%20%5Csqrt%7B8%7D)
The area of a rectangle is given by length times width.
Thus, the area of the given rectangle is given by
Answer:
![{4}^{x - 1} = \frac{49}{4}](https://tex.z-dn.net/?f=%20%7B4%7D%5E%7Bx%20-%201%7D%20%20%3D%20%20%5Cfrac%7B49%7D%7B4%7D%20)
Step-by-step explanation:
My work is in the attachment but I essentially used a hefty bit of Algebraic manipulation to turn 2^x into 4^(x-1) and then isolating that bit.
Comment if you have any questions.
Hope this helped, your welcome!
The answer is (-2,3)
-2 on the x-axis, and 3 on the y axis.
Hope this helps! :)
You have multiply the first numbera and then add the exponents since you are multiplying. The answer is 8.8 x 10^9