Answer:
(-16.494 ; -3.506)
Step-by-step explanation:
student Prob A Prob B difference, d (A-B)
1 20 35____ - 15
2 30 40 ___ - 10
3 15 20 ___ - 5
4 40 50 __ - 10
Difference, d = -15, -10, -5, -10
Xd = Σd/ n = - 40 / 4 = - 10
Standard deviation of d ; Sd = 4.082
The confidence interval for the difference is given as :
Xd ± Tcritical*(Sd/√n)
Tcritical at 95%; df = n - 1 ; 4 - 1 = 3
Tcritical(0.05, 3)). = 3.182
C.I = -10 ± 3.182(4.082/√4)
C.I = -10 ± 6.494462
C. I = (-16.494 ; -3.506)
Answer:
The rate of change for the given function is 6.
Step-by-step explanation:
Given function is:
The interval on which we have to find the rate of change is:
1≤x≤2
Here
a = 1
b = 2
We have to find the values of function on both points
Putting 1 in place of input (x)
Putting x = 2
The rate of change is calculated by using the following formula
Hence,
The rate of change for the given function is 6.
Answer:
28%
Step-by-step explanation:
So I am assuming the numbers are the number of students.
So 64 + 28+ 52 +56 = 200 students
Assuming the 56 outside the diagram are NOT attending either college.
so 56/200 =28%
Answer:
$641
Step-by-step explanation:
Let $p be the original price.
p = 641 (cor. to the nearest dollar)
∴ The original price was $641.
24% ? Is that what you are asking for?