A line passes through the point (6, -2) and has a slope of 4/3 Write an equation in point-slope form for this line.
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Answer:
Change in area=24-48
Step-by-step explanation:
Let s will be the side of square and r will be the radius of circle.
Then two given conditions are
1)dr/dt=2 m/s
2)ds/dt=1 m/s
Area enclosed=(Area of square)-(Area of circle)
Area of square=
Area of circle=
Area enclosed=
dA/dt=2r(dr/dt)-2s(ds/dt)
At s=24,and r=6
dA/dt=2()(6)(2)-2(24)(1)
Change in area=24-48