$2x-3y=12\qquad\text{subtract}\ 2x\ \text{from both sides}\\\\2x-2x-3y=12-2x\\\\-3y=12-2x\qquad\text{divide both sides by (-3)}\\\\\dfrac{-3y}{-3}=\dfrac{12}{-3}+\dfrac{-2x}{-3}\\\\y=-4+\dfrac{2}{3}x$

7 0

2 years ago

Find the distance between the 2 points (6, - 4) and (2, - 7). Please show me how you found it.

Serga [27]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 6}}\quad ,&{{ -4}})\quad 
% (c,d)
&({{ 2}}\quad ,&{{ -7}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{[2-6]^2+[-7-(-4)]^2}\implies d=\sqrt{(2-6)^2+(-7+4)^2}$

5 0

3 years ago