Answer:
No. It is a constant function.
Step-by-step explanation:
The function f(x) = e^2 is not an exponential functional. Rather, it is a constant function. The reason for this is that in f(x) = e^2, there is no x involved on the right hand side of the equation. The approximate value of e is 2.718281, and the approximate value of 2.718281^2 is 7.389051. This means that f(x) = e^2 = 7.389051. It is important to note that for any value of x, the value of the function remains fixed. This is because the function does not involve the variable x in it. The graph of the function will be a line parallel to the x-axis, and the y-intercept will be 7.389051. For all the lines parallel to x-axis, the value of the function remains the same irrespective of the value of x. Also, the derivative of the function with respect to x is 0, which means that the value of the function is unaffected by the change in the value of x!!!
<span>The function h(t) = 210 – 15t has the slope-intercept form of the equation of a straight line. The y-intercept represents the amount h at the very beginning (when t=0). The negative slope (-15) represents the amount by which h will decrease if t is increased by 1.
We are manipulating the value of time, t, so time, t, is the independent variable, and h(t) = y is the dependent variable.</span>
I know this but I can't remember how to do the process.
Answer:
x=-0.625
Step-by-step explanation:
24x+15=0
-15 -15
24x=-15
x=-0.625
Answer: 9
Step-by-step explanation: 105/12=8.75
8 batches are not enough so she should do it one more time to finish