Answer:
y=-3/5x+16
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(13-19)/(5-(-5))
m=-6/(5+5)
m=-6/10
simplify
m=-3/5
y-y1=m(x-x1)
y-19=-3/5(x-(-5))
y-19=-3/5(x+5)
y=-3/5x-15/5+19
y=-3/5x-3+19
y=-3/5x+16
The answer is c, because you have the multiply the sides
14 / 45
56 / 100 reduces to 14 / 45
Clue one tells you it ends in a 4 or 9.
Clue two tells you it has to be 9.
Clue three tells you x + 9 = 10
The number is 19
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
