How to find increasing and decreasing intervals of a function with fraction?
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Given:
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.
At the 95% confidence level, the confidence interval is
1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)
Answer: ($2823.29, $3416.71)
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.
At the 95% confidence level, the confidence interval is
1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)
Answer: ($2823.29, $3416.71)
The correct answer for the given expression is 99.22.
<h3>What is an expression?</h3>Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division
The expression will be solved as:-
E =
E =
E =
E = 99.22
Therefore the correct answer for the given expression is 99.22.
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