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3 years ago

11

Answer pleaseeee!!! :)))

1 answer:

sertanlavr [38]3 years ago

7 0

Answer:

cos B= 7/25

tan B = 24/7

sin B = 24/25

Step-by-step explanation:

cos B= adjacent/hypotenuse = 7/25

tan B = opposite/adjacent = 24/7

sin B = opposite/hypotenuse = 24/25

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Need help on this math study guide

photoshop1234 [79]

8.

2 terms on left side, 3 on right side

9.

All variables count as coefficients, so they’d be 8m, k, and -16k

10.

The constants are just numbers on their own, or without a variable next to it. Here it’d be 10 and -4

6 0

3 years ago

PLEASE SHOW ALL THE STEPS THAT YOU USE TO SOLVE THIS PROBLEM

Mademuasel [1]

Answer:

{x = 1 , y=1, z=0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

{-2 x - y + z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x - 3 y - 2 z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y+0 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y=1, z=0

6 0

3 years ago

What is the value of m(7+9)n, when m = 0.5 and n = 2?

stepladder [879]

Answer:

16

Step-by-step explanation:

Plug things in then use PEMDAS:

m * (7+9) * n

= 0.5 * (7+9) * 2

= 0.5 * 16 * 2

= 16

4 0

2 years ago

Read 2 more answers

The rate of 225 mi in 7 hr written as a unit rate

mel-nik [20]

Answer:

32.14 an hour

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Mr. Morris is going to save money and replace his sailboat's mainsail himself. He must determine the area of the mainsail in ord

Readme [11.4K]

Answer:

Area of parallelogram is 150 square ft

Step-by-step explanation:

Given the parallelogram in the figure whose height is 10 ft and base length is 15 ft.

Area of parallelogram is $base \times height$

= $15\times 10ft^2$

= 150 square ft

now we have to decompose this parallelogram into rectangles and triangles and then to determine the shape.

The given parallelogram KLMN can be decomposed into 2 triangles and one rectangle.

2 right angled triangles KPL and NOM by construction

$KL^{2}=KP^{2}+PL^{2}=10^{2}+2^{2} =100+4=104$

⇒ $KL=\sqrt104=10.2 ft=MN$ (∵ KLMN is a parallelogram)

Hence, dimension of triangles are 10 ft, 2 ft and 10.2 ft

Now rectangle KPON with dimension 15 ft and 10 ft because KP and NO are perpendiculars on LM.

5 0

3 years ago