I have no idea what the "5-D Process" is. However:
2W = L-1
2W + 2L = 74
Add 1 to both sides of the first equation to isolate L.
2W+1 = L
Now substitute this value for L in the second equation:
2W + 2(2W + 1) = 74
2W + 4W + 2 = 74
6W + 2 = 74
6W = 72
W = 72/6 = 12
L = 2W + 1 [from above] = 2(12) + 1 = 24 + 1 = 25.
25 is one more than twice the width. 25 + 25 + 12 + 12 = 50 + 24 = 74
Answer:
Step 6 is missing the fact that the left hand side is raised to the second power.
Step-by-step explanation:
First cancel c from the left hand side by subtracting it from each side:
ax²+bx+c = 0
ax²+bx+c-c = 0-c
ax²+bx = -c
Next cancel a from the left hand side by dividing all terms by a:
ax²/a + bx/a = -c/a
x² + (b/a)x = -c/a
Next we will complete the square. We do this by dividing the second coefficient, b/a, by 2 and then squaring it; (b/a)÷2 = b/2a; (b/2a)² = b²/4a²
Add this to each side:
x²+(b/a)x+(b²/4a²) = -c/a + (b²/4a²)
Next we will find a common denominator on the right hand side. To do this, multiply the first term by 4a (to make the denominator 4a²):
x²+(b/a)x+(b²/4a²) = (-c*4a)/(a*4a) + (b²/4a²)
x²+(b/a)x+(b²/4a²) = -4ac/4a² + b²/4a²
We can write the left hand side as a squared binomial:
(x+b/2a)² = (b²-4ac)/4a²
Take the square root of both sides:
√(x+b/2a)² = √((b²-4ac)/4a²)
x+b/2a = √(b²-4ac)/2a
Subtract b/2a from each side:
x+b/2a - b/2a = √(b²-4ac)/2a - b/2a
x = (-b ± √(b²-4ac))/2a
2y+3=-2/3(x-3)
minus 3 both sides
2y=-2/3(x-3)-3
divide both sides by 2
y=-1/3(x-3)-3/2
ok, so one thing we can do is evaluate numbers super close to it
when x=3.00001, then the result is aprox -1.5
when x=2.99999, the result is -1.5
the value of the limit is -1.5 or -3/2
Answer:
8 1/4
Step-by-step explanation:
Answer:
The function g(x) simply takes the value x and turns it into its reciprocal value . Thus, for instance, the number 5 becomes , and becomes 2. Note that any value of x works in this function as long as is defined. As mentioned, fractions work as well as whole numbers, both for positive and negative values; the only value that does not work is 0, since is undefined (how many times can 0 go into 1?). Thus, the domain of the function is all x in where x ≠ 0. Let's look at the graph of the function also.
Step-by-step explanation:
The function f simply takes in input value x, multiplies it by 2, and then adds 3 to the result. We can therefore consider what constitutes the set of numbers that the function can accept as an input and what constitutes the set of numbers that the function can yield as an output.