We have equation:
t=20x+31
x is number of years after 1997.
To calculate number of laptops in 2005:
x=2005-1997
x=8
t=20*8+31
t=160+31
t=191
In year 2005 school had 191 laptops.
Answer: 3/8
because 3/8 is .375
And 3/4 is .75
And 1/6 is .1666
1/2 is .50
3/8 is closest
Using the future value formula, it is found that you would need to deposit $272.95 in the account each month.
<h3>What is the future value formula?</h3>
It is given by:
![V(n) = P\left[\frac{(1 + r)^{n-1}}{r}\right]](https://tex.z-dn.net/?f=V%28n%29%20%3D%20P%5Cleft%5B%5Cfrac%7B%281%20%2B%20r%29%5E%7Bn-1%7D%7D%7Br%7D%5Cright%5D)
In which:
- n is the number of payments.
For this problem, considering that there are monthly compoundings, the parameters are:
r = 0.08/12 = 0.0067, V(n) = 300000, n = 25 x 12 = 300.
Hence we solve for P to find the monthly payment.
![V(n) = P\left[\frac{(1 + r)^{n-1}}{r}\right]](https://tex.z-dn.net/?f=V%28n%29%20%3D%20P%5Cleft%5B%5Cfrac%7B%281%20%2B%20r%29%5E%7Bn-1%7D%7D%7Br%7D%5Cright%5D)
![300000 = P\left[\frac{(1.0067)^{299}}{0.0067}\right]](https://tex.z-dn.net/?f=300000%20%3D%20P%5Cleft%5B%5Cfrac%7B%281.0067%29%5E%7B299%7D%7D%7B0.0067%7D%5Cright%5D)
1099.12P = 300000
P = 300000/1099.12
P = $272.95.
You would need to deposit $272.95 in the account each month.
More can be learned about the future value formula at brainly.com/question/24703884
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Median is in the middle witch would be 479 and mode is 113
Answer:
No solution
Step-by-step explanation:
This is just a simple system of equations.
y=-1/4x+2
8y+2x=-40
Get the same variables onto their corresponding sides, so it will look like this:
y=-1/4x+2
8y=-2x-40
Now here, you have to be careful, because to solve for the system of equations, you need to make sure you are multiplying the equation proportionately.
8y=-2x+16
8y=-2x+40.
But here you see that they share the same variables in a similar format, but their values are supposed to be different, meaning that this equation is a false claim. So you would respond to the question as "no solution.