Answer: the 2 graph it’s gonna be the answer
First u start in x axis n den u go up y axis so that means that u finna start in one and go up 9 spaces
Answer:
x=5
Step-by-step explanation:
add 5 to both sides
-20+5 = -3x
-15=-3x (divide)
x=5
Step b is wrong. The slope is the change in y over the change in x.
Step b should be (18- 8)/( 10-6)
= 10/4
= 5/2
Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
Answer:
d = 48t will represent the distance 'd' traveled in 't' hours.
Step-by-step explanation:
Jason leaves Detroit at 2:00 PM and passes through Ann Arbor at 2:50 PM which is 40 mi distant from Detroit.
Speed during this journey was constant.
Jason traveled 40 mi in 50 minutes or
hours from Detroit to Ann Arbor.
By the formula,
Speed = 
Speed = 
= 48 mi per hour
If he travels 'd' miles in 't' hours then by the formula of speed,
48 = 
d = 48t