Answer:
KI=11.25 and HI=6.75
Step-by-step explanation:
Consider the below figure attached with this question.
According to Pythagoras Theorem:

Use Pythagoras in triangle HKL




Taking square root on both sides.

Let length of HI be x.
LI = 12+x
Use Pythagoras theorem in ΔKLI,




Use Pythagoras theorem in ΔHKI,


From (1) and (2) we get



Hence, the measure of HI is 6.75 units.
Substitute x=6.75 in equation (2).


Taking square root on both sides.


Hence, the measure of KI is 11.25 units.
Answer:
15.5
Step-by-step explanation:
The equation to find area is Length × Width= Area
we have the area and the length, 12.5 × width= 293.75
to find the width, you will have to reverse engineer and divide the area by the length instead.
193.75 ÷ 12.5 =15.5
just to double check, 15.5 × 12.5 = 193.75
the width is 15.5
Answer:
side angle side. Seems contrary
How much of each solution should the teacher mix together to get 105 ML of 60% sugar solution for an experiment?
1. Look at how 60% is closer to the solution of lower concentration (50%). You can deduce that you will be mixing a higher volume of the 50% solution.
2. All 4 answers add up to 105ml.
3. The intuitive answer is the first option:
70 ML of the 50% solution and 35 ML of the 80% solution
4. Let's check whether point 3 is true.
70ml/105ml X 0.5 + 35ml/105ml X 0.8 = (35 + 28)/105= 63/105= 60% / 105 ml = 105ml of 60% sugar solution
Answer:
-80
Step-by-step explanation:
Subtract 4:
-10 = x/8
Multiply by 8:
-80 = x
The value of x is -80.
_____
This sort of equation is sometimes referred to as a "two-step" linear equation.
<u>Step 1</u>. After you identify the term containing the variable (x/8), you identify any constants on the same side of the equal sign (+4). Add their opposite to both sides of the equation. That gets the variable term by itself.
<u>Step 2</u>. Then identify the coefficient of the variable (1/8). Multiply both sides of the equation by the reciprocal of this value. That will make the coefficient of the variable become 1. The constant on the other side of the equal sign is now the value of the variable.