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3 years ago

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canning operation is designed to fill cans with 14.5 oz of ingredients, on average, with a standard deviation of 0.1 oz. Nine ca

ns are selected at random from the process, and the weights of the nine cans averaged 14.52 oz with a standard deviation of 0.075 oz. The standard error of the sample mean is:

1 answer:

Pavlova-9 [17]3 years ago

3 0

Answer:

SE = 0.025

Step-by-step explanation:

We are given;

Sample mean; x¯ = 14.52

Sample standard deviation; s = 0.075

Sample size; n = 9

Now,formula for standard error of sample mean is;

SE = s/√n

SE = 0.075/√9

SE = 0.075/3

SE = 0.025

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2 years ago

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Step-by-step explanation:

Given

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$cos\theta = \frac{-16}{10\sqrt{26}}$

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Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

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