Tamam öğretmenim ben bir şey var ya o kadar güzel ki sen benim için çok teşekkür ederiz iyi akşamlar canım çok sıkılıyo çok teşekkür ederiz
Answer:
the probability that all tomatoes are sold is 0.919 (91.9%)
Step-by-step explanation:
since the random variable X= number of tomatoes that are demanded, is normally distributed we can make the standard random variable Z such that:
Z=(X-μ)/σ = (83 - 125)/30 = -1.4
where μ= expected value of X= mean of X (since X is normally distributed) , σ=standard deviation of X
then all tomatoes are sold if the demand surpasses 83 tomatos , therefore
P(X>83) = P(Z>-1.4) = 1- P(Z≤-1.4)
from tables of standard normal distribution →P(Z≤-1.4)=0.081 , therefore
P(X>83) = 1- P(Z≤-1.4) = 1 - 0.081 = 0.919 (91.9%)
thus the probability that all tomatoes are sold is 0.919 (91.9%)
How to solve ; -3m + 18 - 4 = 14. that equals -3m+14
Answer:
12 11/35
Step-by-step explanation:
Given Data
First term= 15 3/5
To simple fracrion= 78/5
Second term= 3 2/7
To simple fracrion= 23/7
Hence the operation goes thus
= 78/5- 23/7
LCM = 35
=546-115/35
=431/35
=12 11/35
