Question

A mars rover traveled from point a to point b at a speed of 4 cm/sec. Worsening conditions during the return trip caused the rover to travel at a speed of 2.5cm/sec and increased the travel time by 15 minutes. what is the distance between point a and point b?

Answer 1

Using a system of linear equations, the distance between points A and B is 6000 cm

• Initial speed = 4cm/sec

Time taken = Distance / speed

Let ; distance = d

To time :

• t = d / 4
• 4t = d ______(1)

Fro time :

(t + 15 × 60) = d / 2.5

2.5(t + 900) = d

2.5t + 2250 = d ______(2)

Equate (1) and (2)

4t = 2.5t + 2250

4t - 2.5t = 2250

1.5t = 2250

t = 1500 seconds

From (1) :

d = 4t

d = 4(1500)

d = 6000 cm

Therefore, the distance from point A to B is 6000 cm

Learn more : brainly.com/question/14000187

Answer 2

Answer:

60

Step-by-step explanation:

time * speed

in seconds 60x *4 = 2.5(60x + 900)

x= 25

25 min * 4cm/2

distance = 60 meters

CHEck!!!