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4 years ago

I never got my anwser to finding the product and write the lowest term to 7/54×27/35

Mathematics

1 answer:

kenny6666 [7]4 years ago

4 0

Answer:

Step-by-step explanation:

7 / 54 * 27/35 =

1/2 * 1/5 =

1/10 <===

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A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2

alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0

3 years ago

Expand $3p^5q^3\left( 2pq + \frac{5}{(pq)^2} \right)$. Thank you!

Nikolay [14]

Answer:

idk

Step-by-step explanation:

8 0

3 years ago

Oceans are what percentage of the hydrosphere? <br> a. 71% <br> b. 87% <br> c. 99% <br> d. 97%

Bond [772]

Answer:

71%

Step-by-step explanation:

hydrosphere and biosphere both make sense, but from many searches, it says that at least 70% of Earths SURFACE is covered in water (not describing how deep the water is), so the greatest estimate yet would be 71%

6 0

3 years ago

Read 2 more answers

The Arc Electronic Company had an income of 7676 million dollars last year. Suppose the mean income of firms in the same industr

garri49 [273]

Answer:

0.9772 = 97.72% probability that a randomly selected firm will earn more than Arc did last year

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Suppose the mean income of firms in the same industry as Arc for a year is 90 million dollars with a standard deviation of 7 million dollars.

This means that $\mu = 90, \sigma = 7$

What is the probability that a randomly selected firm will earn more than Arc did last year?

Arc earned 76 million, so this is 1 subtracted by the pvalue of Z when X = 76.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{76 - 90}{7}$

$Z = -2$

$Z = -2$ has a pvalue of 0.0228

1 - 0.0228 = 0.9772

0.9772 = 97.72% probability that a randomly selected firm will earn more than Arc did last year

3 0

3 years ago

Please help me on this question, I’ll give brainliest just pls help me :( i am struggling.

Jlenok [28]

Answer: a associative

b identity

c associative

please mark as brainliest please

6 0

3 years ago