Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.
b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
![= 1 - [^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 * (0.4)^2 (0.6)^3]](https://tex.z-dn.net/?f=%20%20%3D%201%20-%20%5B%5E5C_0%20%20%280.4%29%5E0%20%20%280.6%29%5E5%20%2B%20%5E5C_1%20%20%280.4%29%5E1%20%20%280.6%29%5E4%20%2B%20%5E5C_2%20%2A%20%280.4%29%5E2%20%20%280.6%29%5E3%5D%20)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
Answer: i cant see it
Step-by-step explanation:
The minimum score was 70.
On a box-and-whisker, the dot on the left end is the lowest value.
The first line on the left is the lower quartile.
The second line is the median.
The third line is the upper quartile.
And finally, the dot on right end is the highest value.
Hope I could help :)
When you roll and even number, the probability of winning is 3/6 or 1/2.
When you want to draw a heart:
The sample space is 12. That is 3 faces and 4 suits. There are 4 hearts in this deck. The probability you get a heart is 4/12 or 1/3.
When you want to toss a tail:
Sample<span> space is 2, hea</span>d and tail. You do not win if you get a heads. The probability is 1/2. The probability of winning is 1/2 * 1/3 * 1/2 = 1/12 Then the probability of losing is 1-1/12 = 11/12
