PLEASE HELP i have like 10 mins to answer this... Find the horizontal asymptote of f(x)= -2x^2+3x+6/x^2+1. answer choices: y=-2,

Question

3 years ago

5

y=-1, y=1, y=2

2 answers:

OLga [1] · Answer 1 · 2022-01-29T02:40:01+03:00

OLga [1]3 years ago

5 0

Answer:

6 md 4

Step-by-step explanation:

Makovka662 [10] · Answer 2 · 2022-01-29T03:53:27+03:00

Makovka662 [10]3 years ago

3 0

Answer:

y = -2.

Step-by-step explanation:

Divide -2x^2 + 3x + 6 by x^2 + 1

This gives - 2 + (3x+1)/(x^2 + 1).

So the assymptote is y = -2.