Answer:
x²+ x = 0
x ( x +1 ) = 0
x = -1
x³-25x=0
x ( x² - 25 ) = 0
x² = 25
x = 5
x²=4x
x² - 4x = 0
x ( x- 4 ) = 0
x = 4
4x²-4x=1
4x²-4x - 1 = 0
4 x² - 2x - 2x - 1 = 0
2x ( 2x - 1 ) - 1 ( 2x- 1 ) = 0
2x- 1 ) ² = 0
2x = 1
x = 1/ 2
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Answer:
Step-by-step explanation:
Given that acceleration of an object is
is the solution to the differential equation
Since v(0) =7
we get ln 7 = C
Hence 
since velocity is rate of change of distance s we have
![v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bds%7D%7Bdt%7D%20%3D7e%5E%7B-2t%7D%5C%5Cs%3D%20%5Btex%5Ds%28t%29%20%3D%5Cfrac%7B-7%7D%7B2%7D%20%28e%5E%7B-2t%7D%29%2BC%29%5B)
substitute t=0 and s=0
So solution for distance is
Answer:
x = 2
Step-by-step explanation:
5x - 2 = 10 - x
<em>Add x to both sides</em>
6x - 2 = 10
<em>Add 2 to both sides</em>
6x = 12
<em>Divide both sides by 6</em>
x = 2
Answer:
Round 3 the grandmas
Step-by-step explanation:
The answer is 200 cm³
The volume of the rectangular prism (V1) is:
V1 = l · w · h (l - length, w - width, h - height)
It is given:
h = 12 cm
w = l = 5 cm (since it has a square base which all sides are the same size).
Thus: V1 = 12 · 5 · 5 = 300 cm³
The volume of pyramid (V2) is:
V2 = 1/3 · l · w · h (l - length, w - width, h - height)
It is given:
h = 12 cm
w = l = 5 cm (since it has a square base which all sides are the same size).
V2 = 1/3 · 12 · 5 · 5 = 1/3 · 300 = 100 cm³
The volume of the space outside the pyramid but inside the prism (V) is a difference between the volume of the rectangular prism (V1) and the volume of the pyramid (V2):
V = V1 - V2 = 300 cm³ - 100 cm³ = 200 cm³
