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dexar [7]
3 years ago
5

Which set of expressions represents three consecutive integers?

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0
D, as it increases by one
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A board of length 7 divided by the quantity x minus 2 end of quantity meters was cut into two pieces. If one piece is 3 divided
bulgar [2K]

Answer:

Length of other board =\frac{4x+20}{x^{2} -4} metres

Step-by-step explanation:

Given: Length of board = \frac{7}{x-2} metres

Length of board was divided into two.

Length of one piece = \frac{3}{x+2} metres

Let l = length of the other board

Length of the other board = Length of board - Length of one piece

So, l=\frac{7}{x-2}-\frac{3}{x+2}

l=\frac{7(x+2)-3(x-2)}{(x-2)(x+2)} \\\\l=\frac{7x+14-3x+6}{x^{2} -4} \\\\l=\frac{4x+20}{x^{2} -4}

Thus, length of the other board =\frac{4x+20}{x^{2} -4} metres

4 0
3 years ago
How to figure it out
ollegr [7]
Y = kx
72 = k*3
73/3 = k
24 = k

y = 24x

4 0
3 years ago
Lynnette can wash 959595 cars in 5 days.<br> How many cars can Lynnette wash in 11 days?
aleksley [76]

Answer:

Lynnette can wash 2111109 in 11 days

Step-by-step explanation:

Have a good day :)

6 0
3 years ago
The shape of the sign outside Bob's Burger Barn is a regular octagon. How many degrees are in the measure of an interior angle o
DochEvi [55]

Answer:

An octagon has eight interior angles.

Interior angle total sum = (n-2) x 180, where n = number of sides.

Since an octagon has 8 sides, we have:

6 x 180 / 8, which is 135.

The answer is 135.

Let me know if this helps!

7 0
3 years ago
Read 2 more answers
Decide which chi-square test (goodness-of fit, homogeneity, or independence) would be most appropriate for the given situation.
sasho [114]

Answer:

C. Test for Goodness-of-fit.

Step-by-step explanation:

C. Test for Goodness-of-fit would be most appropriate for the given situation.

A. Test Of  Homogeneity.

The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.

B. Test for Independence.

The chi square  is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.

C. Test for Goodness-of-fit.

The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with  their estimates and provided that one degree of freedom is deducted for each parameter estimated.

4 0
3 years ago
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