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3 years ago

Please please please PLEASE HELP ASAP

Mathematics

1 answer:

Gekata [30.6K]3 years ago

5 0

Answer:

1; -1

Step-by-step explanation:

As x approaches 0 from the left, the graph goes up to the point (0, 1), where the solid dot indicates that is the function definition for x=0.

As x approaches 0 from the right, the graph goes down toward the point (0, -1), to which it comes arbitrarily close. The limit from that direction is -1.

The two limits are +1 and -1.

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The length of the line segment joining the midpoints of sides AB and BC of the parallelogram ABCD is 10. Find the length of diag

solniwko [45]

Answer:

The length of the diagonal AC=20 cm.

Step-by-step explanation:

From ΔOBP and ΔABC, we have

$\frac{OB}{AB}=\frac{BP}{BC}$ ( O and P are mid points)

∠B=∠B(Common)

Therefore, by SAS rule,

ΔOBP is similar toΔABC

Thus, $\frac{OB}{AB}=\frac{OB}{2OB}=\frac{1}{2}$

⇒ $\frac{OP}{AC}=\frac{1}{2}$

⇒ $AC=2{\times}OP$

⇒ $AC=2{\times}10$

⇒ $AC=20 cm$

Thus, the length of the diagonal AC=20 cm.

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3 years ago

A: P = 2L + 2W solve for W<br><br>B: C = 5/9(F - 32) solve for F

aliya0001 [1]

Answer:

A. P/2 - L = W

B. 9/5C + 32 = F

Step-by-step explanation:

A. P = 2L + 2W

P = 2(L+W)

P/2 = L + W

(P/2)-L = W

B. C = 5/9(F - 32)

9/5C = F - 32

9/5C + 32 = F

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3 years ago

Find the missing measurement

Andrei [34K]

Answer:

16 degrees

Step-by-step explanation:

180 degrees = 164 degrees + x,

x = (180 - 164) degrees,

x = 16 degrees

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3 years ago

A 5 meter ladder is positioned 3.2 meters away from a building. A) draw a diagram to represent the information.b) calculate how

Karo-lina-s [1.5K]

Answer:i belive that b is the answer from what i got information wise

Step-by-step explanation:

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3 years ago

Use logarithmic differentiation to find dy/dx. y = (1 + x)^1/x, x > 0

vovangra [49]

Use exp/log functions to rewrite y as

$y = (1+x)^{\frac1x} \implies y = \exp\left(\ln\left(1+x)^{\frac1x}\right)\right)$

One of the properties of logarithms lets us bring down the exponent, so

$y = \exp\left(\dfrac{\ln(1+x)}x\right)$

Now take the derivative of both sides with respect to x. By the chain and quotient rules,

$\dfrac{dy}{dx} = \exp\left(\dfrac{\ln(1+x)}x\right) \times \dfrac{\frac x{1+x} - \ln(1+x)}{x^2}$

Simplify:

$\boxed{\dfrac{dy}{dx} = \frac{x - (1+x)\ln(1+x)}{x^2(1+x)} (1+x)^{\frac1x}}$

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2 years ago