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BlackZzzverrR [31]
3 years ago
12

Please help I will give brainly

Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

the answer is b

Step-by-step explanation:

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Factor 9s^2 - 36s + 35
Verdich [7]

Split the second term in 9s^2 - 36s + 35 into two terms

9s^2 - 15s - 21s + 35

Factor out common terms in the first two terms, then in the last two terms

3s(3s - 5) - 7(3s - 5)

Factor out the common term 3s - 5

<u>(3s - 5)(3s - 7) </u>

4 0
3 years ago
Help please I need the answer
Mazyrski [523]

Answer:

Albany

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
0.2(x + 1) + 0.5x = -0.3(x - 4)?
andreyandreev [35.5K]

Answer:

x=1.....................

7 0
3 years ago
What one is it? help pls
MrMuchimi

Answer:

(-2, 0)

Step-by-step explanation:

the y-intercept is (-2, 0), therefore that the solution.

5 0
3 years ago
A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s
ANTONII [103]
<h2>Hello!</h2>

The answer is:

The ball will hit the ground after t=2.47s

<h2>Why?</h2>

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula.  We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

We are given the function:

h=-5t^{2}-3t+38

Where,

a=-5\\b=-3\\c=38

Then, substituting it into the quadratic equation, we have:

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s

Since negative time does not exists, the ball will hit the ground after:

t=2.473s=2.47s

Have a nice day!

4 0
3 years ago
Read 2 more answers
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