Answer:
Note: The full question is attached as picture below
a) Hо : p = 0.71
Ha : p ≠ 0.71
<em>p </em>= x / n
<em>p </em>= 91/110
<em>p </em>= 0.83.
1 - Pо = 1 - 0.71 = 0.29.
b) Test statistic = z
= <em>p </em>- Pо / [√Pо * (1 - Pо ) / n]
= 0.83 - 0.71 / [√(0.71 * 0.29) / 110]
= 0.12 / 0.043265
= 2.77360453
Test statistic = 2.77
c) P-value
P(z > 2.77) = 2 * [1 - P(z < 2.77)] = 2 * 0.0028
P-value = 0.0056
∝ = 0.01
P-value < ∝
Reject the null hypothesis. There is sufficient evidence to support the researchers claim at the 1% significance level.
Answer:
1.02×10¹ = 10.2
Step-by-step explanation:
We have given a number in scientific notation as follows 1.02×10¹
We need to convert it into standard notation.
1 is in ones place, 0 is in tenths place and 2 is in hundredths place.

So, the standard notation of 1.02×10¹ is 10.2
Answer:
b
Step-by-step explanation:
Answer:
z = - 0.02
Step-by-step explanation:
0.3 = -15z
0.3 / -15 = z
-0.02 = z
Answer:
Step-by-step explanation:
![x_{1}=7 \ ; y_{1} = -4\\\\x_{2} = -8 \ ; y_{2}=5\\\\CD = \sqrt{(-8-7)^{2}+(5-[-4])^{2}}\\\\=\sqrt{(-15)^{2}+(5+4)^{2}}\\\\=\sqrt{225+(9)^{2}}\\\\=\sqrt{225+81}\\\\=\sqrt{306}\\\\=\sqrt{3*3*2*17}\\\\=3\sqrt{34}](https://tex.z-dn.net/?f=x_%7B1%7D%3D7%20%5C%20%3B%20y_%7B1%7D%20%3D%20-4%5C%5C%5C%5Cx_%7B2%7D%20%3D%20-8%20%5C%20%3B%20y_%7B2%7D%3D5%5C%5C%5C%5CCD%20%3D%20%5Csqrt%7B%28-8-7%29%5E%7B2%7D%2B%285-%5B-4%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%28-15%29%5E%7B2%7D%2B%285%2B4%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B225%2B%289%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B225%2B81%7D%5C%5C%5C%5C%3D%5Csqrt%7B306%7D%5C%5C%5C%5C%3D%5Csqrt%7B3%2A3%2A2%2A17%7D%5C%5C%5C%5C%3D3%5Csqrt%7B34%7D)
Distance = 