Pedro and Eva do their homework.

Mathematics

2 answers:

Virty [35]4 years ago

8 0

Answer: 72 minutes

Step-by-step explanation: 84/7=12. 12x6=72.

lutik1710 [3]4 years ago

8 0

Answer : 72 minutes
I’ve just answered the exact question lol

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ivolga24 [154]

1/27 I hope this helps!!!

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3 years ago

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What is 50% of $68? Show all of your work. Use the percent proportion model shown below to set up the equation before you calcul

Natali5045456 [20]

Answer:

$34

Step-by-step explanation:

50% is half of 100%

(Because 50% x 2 = 100%)

Thus, half the money ($68) to find 50%.

So, 68÷2 = 34

Final answer is $34

50/100 x $68 =$34

Hope this helps!

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3 years ago

Someone please help me with q6

Studentka2010 [4]

$\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}\\\\\tan3x=\tan(2x+x)=\dfrac{\tan2x+\tan x}{1-\tan2x\tan x}=\dfrac{\tan(x+x)+\tan x}{1-\tan(x+x)\tan x}\\\\=\dfrac{\frac{\tan x+\tan x}{1-\tan x\tan x}+\tan x}{1-\frac{\tan x+\tan x}{1-\tan x\tan x}\tan x}=\dfrac{\frac{2\tan x}{1-\tan^2x}+\tan x}{1-\frac{2\tan x}{1-\tan^2x}\tan x}$

$=\left(\dfrac{2\tan x}{1-\tan^2x}+\dfrac{\tan x(1-\tan^2x)}{1-\tan^2x}\right):\left(\dfrac{1-\tan^2x}{1-\tan^2x}-\dfrac{2\tan^2x}{1-\tan^2x}\right)\\\\=\dfrac{2\tan x+\tan x-\tan^3x}{1-\tan^2x}:\dfrac{1-\tan^2x-2\tan^2x}{1-\tan^2x}\\\\=\dfrac{3\tan x-\tan^3x}{1-\tan^2x}:\dfrac{1-3\tan^2x}{1-\tan^2x}=\dfrac{3\tan x-\tan^3x}{1-\tan^2x}\cdot\dfrac{1-\tan^2x}{1-3\tan^2x}\\\\=\dfrac{3\tan x-\tan^3x}{1}\cdot\dfrac{1}{1-3\tan^2x}=\dfrac{3\tan x-\tan^3x}{1-3\tan^2x}$