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Blizzard [7]
4 years ago
7

There is 3/4 of pizza leftover from the night before. How many 1/8 portiona are there?

Mathematics
1 answer:
lara [203]4 years ago
6 0

Answer: 6

Step-by-step explanation: First you need to set both denominators equal. To do that you multiply 4 by 2 to get 8. Then you have to multiply the numerator by 2, so 2 times 3 equals 6.

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Un taxi de la empresa “El rápido” se desplaza hacia el sur a una velocidad comprendida entre 60 km/h y 80 km/h. ¿Entre que valor
svetoff [14.1K]

Answer:

Los valores entre los cuales oscila la distancia del automóvil después de 5 horas es entre 300 metros y 400 metros.

Step-by-step explanation:

Dado que la velocidad mínima del taxi = 60 km / h, la velocidad máxima del taxi = 80 km / h

Por lo tanto, tenemos la distancia mínima cubierta después de una hora = 60 km / h × 5 h = 300 m

La distancia máxima recorrida después de una hora = 80 km / h × 5 h = 400 m, lo que da el rango de variación de la distancia recorrida entre 300 my 400 metros.

Donde, la distancia cubierta = x, tenemos

300 metros ≤ x ≤ 400 metros.

6 0
4 years ago
What should be the first step in adding these equations to eliminate y? 12x-2y=-1 + 4x+6y=-4
Sphinxa [80]

Answer:

Multiply the top equation by 3

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
If the discriminate is equal to -2, how many solutions are there
defon

Answer:

huh?

Step-by-step explanation:

6 0
3 years ago
Please verify the following trigonometric identities.
Nina [5.8K]

Seems like there is a correction in the first question (RHS is tanx.tany)

(i) For convenience: let tanx = a ; tany = b

Thus, tanx + tany = a + b

Moreover, cotx = 1/tanx = 1/a ; coty = 1/b

Thus,

cotx + coty = 1/a + 1/b = (a + b)/ab

Hence,

=> (tanx + tany)/(cotx + coty)

=> (a + b) / { (a + b)/ab }

=> ab(a + b)/(a + b)

=> ab => tanx.tany , proved.

(ii) For convenience: let sinx = a ; cosx = b

As we know, sin²x + cos²x = 1 => a²+b²=1

=> (a³ + b³)/(a + b)

=> (a + b)(a² + b² - ab) / (a + b)

=> (a² + b² - ab)

=> 1 - ab => 1 - sinx.cosx , proved

(iii): let x/2 = A

=> tan(x/2) + cosx.tan(x/2)

=> tanA + cos2A.tanA

=> tanA [1 + cos2A]

=> tanA (2cos²A) {1+cos2A = 2cos²A}

=> (sinA/cosA) (2cos²A)

=> sinA (2cosA)

=> 2sinAcosA

=> sin2A

=> sin2(x/2)

=> sinx proved

Letting x/2 = A is not mandatory. I did it to decease words*(in a line).

<u>Indentities used</u>:

• sin²A + cos²A = 1

• (a³ + b³) = (a + b)(a² + b² - 1)

• 1 + cosA = 2 cos²(A/2)

• tanA = sinA/cosA.

• 2sinAcosA = sin2A

8 0
3 years ago
Read 2 more answers
The total surface area of a closed cylinder is
Degger [83]

The maximum volume of the cylinder is 27147.355 at the maximum point  r = \frac{50}{\sqrt{3} } .

<h3>How do you find the maximum volume of the cylinder?</h3>

The formula for the volume of the cylinder v = \pir^{2}h, To find the maximum volume of the cylinder we apply the condition of maxima  \frac{\mathrm{d} v}{\mathrm{d} r} = 0.

Let r cm be the radius and h cm be the height of the closed cylinder.

Then, Total surface area of the cylinder = 2\pi r(r+h)

                                                        5000 = 2\pi r^{2} +2\pi rh

                                                             h =   \frac{5000-2\pi r^{2} }{2\pi rh} .............(1)

Volume of the cylinder v = \pi r^{2} h

Substitute the value of h in the above equation

\Rightarrow                                       = \pi r^{2} × \left [ \frac{5000-2\pi  r^{2}}{2\pi r} \right ]

\Rightarrow                                      = \frac{r}{2} ×  (5000-2\pi r^{2} )

\Rightarrow                                    v = 2500r-\pi r^{3} ..............(2)

Now, for the maximum volume of the cylinder  \frac{\mathrm{d} v}{\mathrm{d} r} = 0

\Rightarrow                                                            \frac{\mathrm{d} (2500r-\pi r^{3})}{\mathrm{d} r} = 0

\Rightarrow                                                                      3\pi r^{2} = 2500

\Rightarrow                                                                          r^{2} = \frac{2500}{3\pi }

\Rightarrow                                                                          r = \frac{50}{\sqrt{3\pi } }

Volume is maximum for  r = \frac{50}{\sqrt{3\pi } }  

Then, v = 2500r-\pi r^{3}

\Rightarrow              =  2500 \frac{50}{\sqrt{3\pi } } -\pi (\frac{50}{\sqrt{3\pi } } )^{3}                              

\Rightarrow             = \frac{125000}{\sqrt{3\pi } } - \frac{125000}{3\sqrt{3\pi } }

\Rightarrow             = \frac{125000}{\sqrt{3\pi } }×\frac{2}{3}

\Rightarrow             = \frac{250000}{3\sqrt{3\pi } }                                                              

\Rightarrow          v = 27147.355

Hence, The maximum volume of the cylinder is 27147.355 at the maximum point  r = \frac{50}{\sqrt{3} } .                                                

To learn more about total surface area and volume of the cylinder from the given link

brainly.com/question/16095729

#SPJ4                                                                                   

3 0
2 years ago
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