I think the answer is 2 weeks 6 days because if over the course of 2 weeks they took 12 I ready quizzes the he needs 18 quizzes and it leaves 1 day extra
The two inequalities formed will be:
One for ticket quantity:
x + y ≤ 600
One for funds generated via tickets:
5x + 7y ≥ 3500
Equating x to 330,
5(330) +7y ≥ 3500
y = 265
Checking if the other inequality holds true:
330 + 265 ≤ 600
595 ≤ 600
This inequality is still true so they can sell 265 tickets on the event day and cover their expenses.
Answer:
x=5
AOB = 8
BOC = 13
AOC = 21
Step-by-step explanation:
<em>Angle AOB and Angle BOC is equal to Angle AOC.</em>
AOB = x+3
BOC = 4x-7
AOC= 2x+11
AOB + BOC = AOC
x+3+4x-7 = 2x+11
5x-4 = 2x+11
3x = 15
x = 5
Therefore, the value of x is 5.
<em>Angle AOB = x+3</em>
AOB = 5+3
AOB = 8
<em>Angle BOC = 4x-7</em>
BOC = 4(5)-7
BOC = 13
<em>Angle AOC = 2x+11</em>
AOC = 2(5)+11
AOC = 21
!!
Answer:
- 33 1/3 liters of 30%
- 16 2/3 liters of 45%
Step-by-step explanation:
Let x represent the liters of 45% solution needed. Then the amount of HCl in the mix is ...
0.45x +0.30(50 -x) = 0.35(50)
0.15x = 0.05(50) . . . . . simplify, subtract 0.30(50)
x = (0.05/0.15)(50) = 50/3 = 16 2/3 . . . liters of 45% HCl
33 1/3 liters of 30% and 16 2/3 liters of 45% HCl are needed.
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<em>Comment on the solution</em>
You may notice that the general solution to a mixture problem of this sort is that the fraction of the mix that is the highest contributor is ...
(mix % - low %) / (high % - low %) = (.35 -.30) / (.45 -.30) = .05/.15 = 1/3
