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3 years ago

The total cost of c ounces of cinnamon if each ounce costs$.79

Mathematics

1 answer:

Anit [1.1K]3 years ago

8 0

The total cost of c ounces of cinnamon would be $0.79c

Since each ounce costs $0.79, just multiply this number by the number of ounces to get the cost.

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Sally has 10 pounds she wants to buy 28 cans of soda which cost 28p each does she have enough money

Vladimir79 [104]

Answer:

Yes, Sally has enough money to buy 28 cans of soda.

Step-by-step explanation:

Yes, because £10 = 1000p

1000p / 28p = 35 cans

35 cans < 28 cans

So Sally has enough money for 28 cans.

4 0

2 years ago

FIND (-8/3)+(-1/4)+(-11/6)+3/8-3

emmainna [20.7K]

Answer:

-7 3/8

Step-by-step explanation:

The least common denominator of 3, 4, 6, and 8 is 24; converting all of our fractions to that denominator and solving, we have

$-\frac{8}{3}+\left(-\frac{1}{4}\right)+\left(-\frac{11}{6}\right)+\frac{3}{8}-3\\=-\frac{64}{24}+\left(-\frac{6}{24}\right)+\left(-\frac{44}{24}\right)+\frac{9}{24}-3\\\\=\frac{-64+(-6)+(-44)+9}{24} -3\\\\=\frac{-70+(-44)+9}{24} -3\\\\=\frac{-114+9}{24} -3\\\\=\frac{-105}{24}-3 \\\\=\frac{-35}{8}-3\\ \\=-4\frac{3}{8}-3\\\\=-7\frac{3}{8}$

So our solution is -7 3/8

8 0

3 years ago

How do you illustrate quadratic equation in one varible?<br>

kvasek [131]

Answer:

A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable. One absolute rule is that the first constant "a" cannot be a zero.

Step-by-step explanation:

6 0

3 years ago

Need help with this....

Yakvenalex [24]

Answer:

$\boxed{\dfrac{f(a+h)-f(a)}{h}=-3a^2-3ah-h^2}$

Step-by-step explanation:

$f(x)=-x^3+2\\\\\dfrac{f(a+h)-f(a)}{h}\\\\f(a+h)\to\text{substitute x = a + h}\\f(a)\to\text{substitute x = a}\\\\\dfrac{f(a+h)-f(a)}{h}=\dfrac{-(a+h)^3+2-(-a^3+2)}{h}\\\\\text{use}\ (x+y)^3=x^3+3x^2y+3xy^2+y^3\\\\=\dfrac{-(a^3+3a^2h+3ah^2+h^3)+2-(-a^3)-2}{h}\\\\=\dfrac{-a^3-3a^2h-3ah^2-h^3+2+a^3-2}{h}\\\\\text{combine like terms}$

$=\dfrac{(-a^3+a^3)-3a^2h-3ah^2-h^3+(2-2)}{h}\\\\=\dfrac{-3a^2h-3ah^2-h^3}{h}\\\\=\dfrac{h(-3a^2-3ah-h^2)}{h}\\\\=-3a^2-3ah-h^2$

6 0

3 years ago

3-2y+(-8y)+8.5<br><br> Simplify your answer. Use interfere or decimals for any number expressions

Nataly_w [17]

Im pretty sure it’s 11.5 - 16y

8 0

3 years ago