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Bumek [7]
3 years ago
9

Jim had 92 more marbles than Sam. After Sam gave Jim 18 marbles, Jim had twice as many marbles as Sam. How many marbles did Jim

have at first?
Mathematics
2 answers:
Mariana [72]3 years ago
8 0

Answer is 27.5

= 92+18

=110 divided by 2

=55

Haha this is wrong

Ede4ka [16]3 years ago
7 0

Answer:

238

Step-by-step explanation:

let the number of marbles Sam has be x, then

Jim has x + 92 ← 92 more than Sam

After swap of 18 marbles

Sam has x - 18 and sam has x + 92 + 18 = x + 110

Jim now has twice as many as Sam, that is

x + 110 = 2(x - 18)

x + 110 = 2x - 36 ( subtract x from both sides )

110 = x - 36 ( add 36 to both sides )

146 = x

At first Jim had 146 + 92 = 238 marbles

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liubo4ka [24]
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  • Height=h

\boxed{\sf Volume=\pi r^2h}

\\ \sf\longmapsto π(0.7)^2h=231

\\ \sf\longmapsto 0.49πh=231

\\ \sf\longmapsto πh=\dfrac{231}{0.49}

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