What is the value of the expression (x – y 2 when x = 5 and y = –1 ?
1 answer:
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Answer:
Option A
Step-by-step explanation:
By applying Pythagoras theorem in ΔABC,
(Hypotenuse)² = (Leg 1)² + (Leg 2)²
AC² = AB² + BC²
AC² = 6² + 5²
AC =
Similarly, by applying Pythagoras theorem in ΔACD,
AD² = AC² + CD²
(10)² = + x²
x² = 100- 61
x² = 39
x = √(39)
Option A will be the answer.
