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3 years ago

What is an equivalent numerical expression to 5+(8-4) ÷2+3

1 answer:

4 0

5+4 ÷2+3 or 5+2+3. you have to follow the order of PEMDAS..
P(arenthesis)
E(xponents)
M(ultiplication)
D(ivision)
A(ddition)
S(ubtraction)

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Round 98,471 to the nearest ten thousands

d1i1m1o1n [39]

The answer to this question is 98000

4 0

3 years ago

Out of 27 participants in a track race, 5 are from China, 4 from the U.S.A., 3 each from the U.K. and Russia, and the rest from

son4ous [18]

I think it is 4 out of 5 but i dont know the number to the nearest thousanths
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3 years ago

A large spherical balloon is being deflated. When the radius of the balloon decreases from 10 ft to 5 ft, approximately how much

Xelga [282]

Volume of a sphere: V=(4/3)πr³
V1=(4/3)π10³
V2=(4/3)π5³
difference: (4/3)π10³-(4/3)π5³=(4/3)π875=3665
the answer is B.<span />

5 0

3 years ago

Read 2 more answers

If we wanted to create a new 90% confidence interval from a different sample for the proportion of those with a two on one date

slava [35]

Answer: 271

Step-by-step explanation:

The formula we use to find the sample size is given by :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

, where $z_{\alpha/2}$ is the two-tailed z-value for significance level of $(\alpha)$

p = prior estimation of the proportion

E = Margin of error.

If prior estimation of the proportion is unknown, then we take p= 0.5 , the formula becomes

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2$

$n=0.25(\dfrac{z_{\alpha/2}}{E})^2$

Given : Margin of error : E= 0.05

Confidence level = 90%

Significance level $\alpha=1-0.90=0.10$

Using z-value table , Two-tailed z-value for significance level of $0.10$

$z_{\alpha/2}=1.645$

Then, the required sample size would be :

$n=0.25(\dfrac{1.645}{0.05})^2$

Simplify,

$n=270.6025\approx271$

Hence, the required minimum sample size =271

3 0

3 years ago

Emichee can you help me? A cylinder has a base with a radius of 8 inches and a height of 15 inches. What is the volume of the cy

Lina20 [59]

The volume of a Cylinder is:

$V=A_b*h$

the base is a circle, so

$A_b=\pi*r^2$

replacing

$V=\pi*r^2*h$

now we have the values

$V=3.14*8^2*15$

$\boxed{\boxed{V=3014.4~in^3}}$

7 0

3 years ago