Answer:
Step-by-step explanation:
- Option A
![[x+5=20]](https://tex.z-dn.net/?f=%5Bx%2B5%3D20%5D)
tells us that: When we add 5 to a variable x, we get 20. As it has a unique value for x and is completely equal to it(i.e. 15), It is an equality.
- Option B
![[x=5]](https://tex.z-dn.net/?f=%5Bx%3D5%5D)
tells us that: A variable x equals to 5. Hence, as x is unique for 5 and is wholly equal to it, it's an equality too. - Option C
tells us that: A variable x isn't 5 but lesser than it. As we cannot equate it to 5, nor we are given the nature of the variable x, it is an Inequality. - Option D
![[x+5]](https://tex.z-dn.net/?f=%5Bx%2B5%5D)
is an expression; It can't be called an equation or an inequality unless we relate it with another expression.
Answer:
Relateable
Step-by-step explanation:
Obama
You would divide because the amount of gallons is greater than the number of cups.
Ex: there are 16 cups how many gallons
1 gallon divide. 16/16
The question is incomplete. The complete question is :
Victor is selling lemonade to raise money for his school. The amount of money he collected from his sales each day is summarized on the box plot below.
What is the interquartile range of the data ?
Answer:
$ 7
Step-by-step explanation:
It is given that Victor sold lemonade in order to raise money for his school.
The money that Victor collected is shown on the diagram below.
Therefore, we find the interquartile range. It is the difference between the 3rd quartile and the 1st quartile, i.e.
IQR = 
Now from the figure, the 3rd quartile is the value that is at the end of the rectangular box towards the right. Therefore, the 3rd quartile is = $ 29
Similarly from the figure the 1st quartile at the beginning of the rectangular box to the left is = $ 22
So the interquartile range is = 3rd quartile - 1st quartile
= 29 - 22
= $ 7
Thus the amount of money Victor collected is $ 7.
Answer:
ef,ge,fg
Step-by-step explanation:
