All categories

3 years ago

Can anyone please help me! if solve it I will give 30 points and brainliest.

Mathematics

1 answer:

NeTakaya3 years ago

6 0

The biggest cone that can fit into a cube of side 3cm would have a diameter of 3 and height of 3, therefor if the volume of a cone = πr^2h*1/3, then:
Volume = π*1.5^2*3*1/3
= 2.25π
= 9π/4 cm^3

You might be interested in

Bonnie claims single with 2 federal withholding allowances, and contributes state tax of 20% of her federal tax. Below is a copy

Tcecarenko [31]

Answer:

The given net pay is not correct because the medicare is not 1.45% of her gross pay. The medicare should be $11.02, making the correct net pay $641.86

Step-by-step explanation:

3 0

3 years ago

Victor writes 10 more poems than ann.Ann writes 10 poems. How many poems does victor writes?

tino4ka555 [31]

Victor writes 20 poems

Solution:

Given that victor writes 10 more poems than Ann

Also given that Ann writes 10 poems

To find: number of poems written by Victor

From given information, we can frame a equation as:

number of poems written by Victor = 10 more poems than Ann

number of poems written by Victor = 10 + number of poems written by Ann

Substituting the given , number of poems written by Ann = 10 , we get,

number of poems written by Victor = 10 + 10 = 20

Thus victor writes 20 poems

3 0

2 years ago

Read 2 more answers

Suppose a man offered to work for 30 days at the following salary: one cent for the first day two cents for the second day four

Ivahew [28]

It would be to little because it would only be 30 cents

8 0

3 years ago

A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei

ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is $576\ cm^{3}$

Part 2) The total surface area of the paperweight is $400\ cm^{2}$

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the square base

H is the height of the pyramid

$B=8^{2}=64\ cm^{2}$

$H=3\ cm$

substitute

$V=\frac{1}{3}(64)(3)=64\ cm^{3}$

step 2

Find the volume of the cube

The volume of the cube is equal to

$V=b^{3}$

$V=8^{3}=512\ cm^{3}$

step 3

Find the volume of the paperweight

$64\ cm^{3}+512\ cm^{3}=576\ cm^{3}$

Part 2) what is the total surface area of the paperweight?

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

$SA=5b^{2}$

$SA=5(8^{2})=320\ cm^{2}$

step 2

Find the lateral area of the pyramid

$LA=4[\frac{1}{2}bh]$

$LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}$

step 3

Find the total surface area of the paperweight

$320\ cm^{2}+80\ cm^{2}=400\ cm^{2}$

8 0

3 years ago

I don't understand this!

Novosadov [1.4K]

Count the total number of objects. That is the denominator, which goes under the line. Then, only count the stars. That number is the numerator, which goes on top.

4 0

3 years ago