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4 years ago

Write a linear equation given a slope of 6 and a y-intercept of 1/2

Mathematics

2 answers:

Alex777 [14]4 years ago

7 0

it literally gave you the equation lol

y= 6x + 1/2

strojnjashka [21]4 years ago

6 0

Answer:y=6x+1/2

Step-by-step explanation:

y=mx+c

m=slope

y-intercept=c

Our equation would be y=6x+1/2

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Bryan drives at an average speed of 60 miles per hour.

riadik2000 [5.3K]

Answer:

180

Step-by-step explanation:

Multiply 60x3

and you will get 180miles

3 0

3 years ago

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Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

John is building a fence around his home currently his fence measures 14 feet on each side but he wants to increase only the wid

nalin [4]

Answer:

The dimensions of rectangular fence are 14 feet and 20 feet.

Step-by-step explanation:

We are given the following in the question:

Length of rectangular fence = 14 feet

Width of fence = (14+x) feet

Area of rectangular field = 280 square feet

Area of rectangular field =

$A= \text{Length}\times \text{Width}$

Putting the values, we get,

$280 = 14(14+x)\\\\14 + x = \dfrac{280}{14}\\\\14 + x = 20\\x =20-14\\x = 6$

Thus, the dimensions of rectangular fence are 14 feet and 20 feet.

7 0

3 years ago

What the min, max, lower quartile, upper quartile, and median on the photo.

Pie

Answer:

Minimum: 14 Maximum: 87.5 Lower Quartile: 34 Upper Quartile: 65 Median: 47.5

Step-by-step explanation:

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3 years ago

Please find answer.

melisa1 [442]

Answer: (x 1 ,y 1)=(2,3) and (x 2,y 2)=(4,7)by midpoint formula, coordinates of mid point =( 2x 1+x 2, 2y 1 +y 2)=( 22+4, 23+7 )=( 26 , 210)=(3,5).

Step-by-step explanation: Hope this helps

4 0

3 years ago

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