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Mashcka [7]
2 years ago
7

John is building a fence around his home currently his fence measures 14 feet on each side but he wants to increase only the wid

th of his fence by x feet to have a rectangular fence that has an area of 280 square feet write an equation that can be used to find x then solve your problem equation
Mathematics
1 answer:
nalin [4]2 years ago
7 0

Answer:

The dimensions of rectangular fence are 14 feet and 20 feet.

Step-by-step explanation:

We are given the following in the question:

Length of rectangular fence = 14 feet

Width of fence = (14+x) feet

Area of rectangular field = 280 square feet

Area of rectangular field =

A= \text{Length}\times \text{Width}

Putting the values, we get,

280 = 14(14+x)\\\\14 + x = \dfrac{280}{14}\\\\14 + x = 20\\x =20-14\\x = 6

Thus, the dimensions of rectangular fence are 14 feet and 20 feet.

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A bulletin board measuring 28 dm long was divided among three subject areas in the ratio 2:2:3. How much space was alothed for e
Sphinxa [80]

Answer: Space was alloted for each subject is 8 dm, 8 dm, 12 dm.

Explanation:

Since we have given the length of bulletin board =28 dm

Let the share of three subject areas be 2x,2x,3x

According to question,

2x+2x+3x=28\\7x=28\\x=\frac{28}{7}\\x=4dm

so x=4 dm

Now,

Space was alloted for each subject is given as below:

First subject =2x=2\times 4=8 dm

Second subject =2x=2\times 4=8 dm

Third subject =3x=3\times 4=12 dm

4 0
2 years ago
What is the solution of the system? Use either the substitution method or the elimination method. 4x + 2y = 104x + 2y = 10 x − y
bixtya [17]
4x+2y=10 Equation 1
x-y=13 Equation 2
Solving by substitution method.
Isolate x from equation 2.
x=y+13
Substitute value of x in equation 1
4(y+13)+2y=10
4y+52+2y=10
6y+52=10
6y=-42
y=-7
Now substitute value of y in x=y+13
x=-7+13
x=6

Answer: (6,-7)
8 0
3 years ago
I’ll mark you brainliest!!!
notka56 [123]
Answer:
C. (1,18)
Explanation
If you don’t know how to find it, just plug in the values into the equation until they are equal to each other
3 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through the points (5, -9) and (5,8). Put your answer in fully reduced point-slope fo
pantera1 [17]

Answer:

x=5 is what i got from a calculaotr

Step-by-step explanation:

Hello! Thanks for letting me answer your question! If you have any more questions feel free to ask me! If not, Have a WONDERFUL day and Please don't forget to consider making me Brainliest on your question today!

5 0
2 years ago
3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k
Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt

Evaluate the integral to solve for y :

\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt

\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x

\displaystyle y = x^3+2x^2+kx - 2

Use the other known value, f(2) = 18, to solve for k :

18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}

Then the curve C has equation

\boxed{y = x^3 + 2x^2 + 2x - 2}

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2

The slope of the given tangent line y=x-2 is 1. Solve for a :

3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1

So, the point of contact between the tangent line and C is (-1, -3).

7 0
2 years ago
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