4+(5-3)5+7 = 4+2*5+7 = 4+10+7 = 21
Try substituting those values, and you will see they do not fit either equation.
looking at the 2nd equation, y = x+2, so
x+2 = x^2+5x-3
x^2 + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5 or 1
so, y = -3 or 3
the solutions are thus (-5,-3)(1,3)
Hope this helps
Please give me Brainliest
Answer:

Step-by-step explanation:
To find the number midway between 3/2 and 4/2, add them up and divide by 2
we have, 3/2 + 4/2 = 7/2
7/2 ÷ 2 = 7/4
Repeat the same for the number midway between 1/2 and 2/2 to get 3/4
The answer then is, 7/4 - 3/4 = 4/4
Answer: I’m pretty sure it’s c also
The answer for your problem is