Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
the number
the type
Step-by-step explanation:
I believe the 4th one
an=145+an-1 and a1=20
1:100 because 20 divide by 20=1 and 2000 divide by 20 =100
Step-by-step explanation:
how where is the graph cause I don't understand that