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3 years ago

What is the solution to this equation 5= 2/5 a

Mathematics

1 answer:

ira [324]3 years ago

7 0

Answer:

Need more explanation

Step-by-step explanation:

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What is the solution to the equation below? Round your answer to two decimal places. HELP PLEASE PLEASE HELP PLEASE ASAP PLEASE

Assoli18 [71]

the award is a x=1.43

6 0

4 years ago

3 Find y if the slope between ( – 7, y) and (1, 13) is 3/4

mafiozo [28]

Step-by-step explanation:

$slope \: = \frac{y2 - y1}{x2 - x1} = \frac{3}{4}$

point 1 ( -7,y)

point 2 (1,13)

$\frac{13 - y1}{1 - ( - 7)} = \frac{3}{4}$

$\frac{13 - y1}{8} = \frac{3}{4}$

$13 - y2 = \frac{8 \times 3}{4} = 6$

$y2 = 13 - 6 = 7$

y = 7

3 0

3 years ago

Calculate the sum.<br> 10+ (-42)<br> O A. 52<br> O B. -32<br> O C. 32<br> D. -52

kotykmax [81]

Answer:

Step-by-step explanation:

10 + (-42)

10 - 42

-32

8 0

3 years ago

why write a quadratic function whose graph has the given characteristics vertex :(2,3) point on graph (0,-1)

GaryK [48]

<h3>Answer:</h3>

f(x) = -(x -2)² +3

<h3>Step-by-step explanation:</h3>

We can fill in the vertex (h, k) values immediately in the vertex form ...

... f(x) = a(x -h)² +k

To find the value of a, we solve the equation for a at some point other than the vertex. The given point is (0, -1), so we can use that:

... -1 = a(0 -2)² +3

... -4 = 4a . . . . . . . . . subtract 3, simplify

... -1 = a . . . . . . . . . . . divide by 4

Now, we know the function is ...

... f(x) = -(x -2)² +3

5 0

3 years ago

A certain radioactive material decays in such a way that the mass in kilograms remaining after t years is given by the function

Angelina_Jolie [31]

The mass of radioactive material remaining after 50 years would be 48.79 kilograms

<h3>How to determine the amount</h3>

It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.

Given the radioactive decay formula as

m(t)=120e−0.018t

Where

t= 50 years

m(t) is the remaining amount

Substitute the value of t

$m(t) = 120e^-^0^.^0^1^8^(^5^0^)$

$m(t) = 120e^-^0^.^9$

Find the exponential value

m(t) = 48.788399

m(t) = 48.79 kilograms to 2 decimal places

Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms

Learn more about half-life here:

brainly.com/question/26148784

#SPJ1

7 0

2 years ago