Answer:
a) 115°
b) 140°
c) 75°
d) 255°
Step-by-step explanation:
a) another line parallel to AB through E will split x into two sectors.
Parallel lines intersected by a third line makes opposite internal angles of equal value. Supplemental angles add to 180°
x = (180 - 120) + (180 - 125) = 115°
b) double application of parallel lines intersected by a third line making corresponding angles identical.
c) more of the same
d) more of the same
Answer:
21 ft by 28 ft
Step-by-step explanation:
To maximize the area, see the attached.
Perimeter will be 4l+3w which is equal to the fencing perimeter, given as 168
4l+3w=168
Making l the subject then
4l=168-3w
l=42-¾w
Area of individual land will be lw and substituting l with l=42-¾w
Then
A=lw=(42-¾w)w=42w-¾w²
A=42w-¾w²
Getting the first derivative of the above with respect to w rhen
42-w6/4=0
w6/4=42
w=42*4/6=28
Since
l=42-¾w=42-¾(28)=21
Therefore, maximum dimensions are 21 for l and 28 for w
Just subtract 7 from 25. it is 18
Area of shaded region = Area of larger circle - Area of smaller circle.
We know, Area of a Circle = πr²
So, A = πr₁² - πr₂²
A = π (r₁² - r₂²)
A = π(10.2² - 5.4²)
A = 3.14 (104.04 - 29.16)
A = 3.14 (74.88)
A = 235.12
In short, Your Answer would be 235.12 cm²
Hope this helps!