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Gelneren [198K]
4 years ago
15

A line and a plane are considered parallel if they have no points in common

Mathematics
1 answer:
stealth61 [152]4 years ago
5 0

True________________________________________
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find the percent of each school day ( based upon a 24 hour day) budgeted for the following activities. sleep 7.5hr​
I am Lyosha [343]

Step-by-step explanation:

Given:

Sleep hour = 7.5 hr

Assume;

School hour = 6 hr

Homework = 2.5 hr

Eating and playing = 5 hr

Free time = 3 hr

Find:

Percent of each school day

Computation:

Sleep hour = 7.5 hr = [7.5/24]100 = 31.25%

School hour = 6 hr = [6/24]100 = 25%

Homework = 2.5 hr = [2.5/24]100 = 10.41%

Eating and playing = 5 hr = [5/24]100 = 20.83%

Free time = 3 hr = [6/24]100 = 12.5%

6 0
3 years ago
Use the theorem in Sec. 28 to show that if f (z) is analytic and not constant throughout a domain D, then it cannot be constant
alexandr1967 [171]

Answer:

The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.

Step-by-step explanation:

Given

For any given function f(z), it is analytic and not constant throughout a domain D

To Prove

The function f(z) is non-constant constant in the neighbourhood lying in D.

Proof

1-Assume that the value of f(z)  is analytic and has a constant throughout some neighbourhood in D which is ω₀

2-Now consider another function F₁(z) where

F₁(z)=f(z)-ω₀

3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.

4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.

5-Replacing value of F₁(z) in the above gives:

F₁(z)≡0 in domain D

f(z)-ω₀≡0 in domain D

f(z)≡0+ω₀ in domain D

f(z)≡ω₀ in domain D

So this indicates that the value of f(z) for all values in domain D is a constant  ω₀.

This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.

6 0
3 years ago
Multiply the polynomial x (3x-1)(2x+5) also what is the degree of the polynomial
Readme [11.4K]

Answer:

Result after multiplication of polynomial is: 6x^3+13x^2-5x

Degree of polynomial = 3

Step-by-step explanation:

The given polynomials are:

x(3x-1)(2x+5)

In order to multiply the given polynomials we have to work step by step. First of all the polynomials in the bracket will be multiplied and then their result will be multiplied with x.

So, multiplying the polynomials in round brackets first

=x(3x-1)(2x+5)\\= x\{3x(2x+5)-1(2x+5)\}\\=x\{6x^2+15x-2x-5\}\\=x(6x^2+13x-5)

Now multiplying with x

= 6x^3+13x^2-5x

Degree of a polynomial is the highest exponent of variable in the polynomial.

In the acquired result, the highest exponent of x is 3 so the degree is 3.

Hence,

Result after multiplication of polynomial is: 6x^3+13x^2-5x

Degree of polynomial = 3

3 0
3 years ago
Two points are located at (−9,−8) and (−6,−4).
Mrac [35]

Answer:

l(AB)=5\ units

is the distance between the point A and point B.

Step-by-step explanation:

Let

A ≡ (x₁, y₁) ≡ (-9 , -8 )

B ≡ (x₂, y₂) ≡ (-6 , -4 )

Now by Pythagoras  Distance formula we have

a² + b² = c²

l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}\\\\l(AB) = \sqrt{((-6--9)^{2}+(-4--8)^{2} )}\\\\l(AB)=\sqrt{(3)^{2}+(4)^{2}  }\\\\l(AB) =\sqrt{25} \\\\l(AB) = 5\ units

4 0
3 years ago
Read 2 more answers
What is n/2=−7? Thanks!
Rudik [331]
N=-14
-7×2 is -14
you do the opposite when finding a letter
3 0
3 years ago
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