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pshichka [43]
3 years ago
11

If the measure of BEC is (2x+3) and x=30, which expression could represent the measure of AED?

Mathematics
2 answers:
Rufina [12.5K]3 years ago
5 0

Thats means angle BEC is 63. By the vertical angle theorem AED is the same. 3x-27 when x=30 is also 63.

marysya [2.9K]3 years ago
3 0

Step One

Find <BEC

<BEC = 2x + 3 x = 30

<BEC = 2*30+3

<BEC = 60 + 3

<BEC = 63

Step Two

Find AED

<AED = <BEC Why? because the 2 angles are vertically opposite. Vertically opposite angles are equal.

Step Three

Now you have to find which given expression equals 63. Remember that the value of x has not changed. x = 30.

A is wrong 4x = 4*30 = 120. That is far too large.

B 3x - 27 looks good because the answer will end in a 3. 3*30 - 27 = 90 - 27 = 63. The answer is B.

C is wrong because 5x = 5*30 = 150. It's already too big.

D is wrong because 30 + 43 = 73. This is your second best answer, but it is still incorrect.

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<h3>Answer:  36.4 units  (choice A)</h3>

===========================================================

Explanation:

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D = (x_1,y_1) = (-7,2) \text{ and } E = (x_2, y_2) = (3,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-7-3)^2 + (2-4)^2}\\\\d = \sqrt{(-10)^2 + (-2)^2}\\\\d = \sqrt{100 + 4}\\\\d = \sqrt{104}\\\\d = \sqrt{4*26}\\\\d = \sqrt{4}*\sqrt{26}\\\\d = 2\sqrt{26}\\\\d \approx 10.198\\\\

Note: uppercase D refers to the point, while lowercase d is the distance from D to E.

The length of segment DE is roughly 10.198 units long.

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Repeat for the distance from E to F.

E = (x_1,y_1) = (3,4) \text{ and } F = (x_2, y_2) = (5,-7)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-5)^2 + (4-(-7))^2}\\\\d = \sqrt{(3-5)^2 + (4+7)^2}\\\\d = \sqrt{(-2)^2 + (11)^2}\\\\d = \sqrt{4 + 121}\\\\d = \sqrt{125}\\\\d = \sqrt{25*5}\\\\d = \sqrt{25}*\sqrt{5}\\\\d = 5\sqrt{5}\\\\d \approx 11.1803\\\\

Segment EF is roughly 11.1803 units long.

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Repeat for the distance from F to D.

F = (x_1,y_1) = (5,-7) \text{ and } D = (x_2, y_2) = (-7,2)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(5-(-7))^2 + (-7-2)^2}\\\\d = \sqrt{(5+7)^2 + (-7-2)^2}\\\\d = \sqrt{(12)^2 + (-9)^2}\\\\d = \sqrt{144 + 81}\\\\d = \sqrt{225}\\\\d = 15\\\\

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----------------

Add up the three segment lengths to get the perimeter

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The answer has been confirmed with GeoGebra.

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