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zaharov [31]
1 year ago
5

Draw the circle ( x − 1 ) 2 + ( y + 2 ) 2 = 9

Mathematics
1 answer:
MArishka [77]1 year ago
3 0

The required circle will have a radius of 3 units and centre at (1, -2)

<h3>Equation of a circle</h3>

The standard equation of a circle is expressed as shown;

(x-a)^2+(y-b)^2 = r^2

where

(a, b) is the centre of the circle

r is the radius of the circle

Given the equation of the circle below;

(x − 1)^2 + (y + 2)^2 = 9

(x − 1)^2 + (y + 2)^2 = 3^2

Find the centre and radius

centre = (1, -2)

radius = 3

This shows that the required circle will have a radius of 3 units and centre at (1, -2)

Learn more on equation of a circle here: brainly.com/question/14150470

#SPJ1

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For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

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On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

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The given line is:

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We substitute the given point to find "b":

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y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)

ANswer:

y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)

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