Ask question

Ask question

All categories

3 years ago

6

Veronica jogged 10 3/16 miles in one week. The next week she jogged 8 7/16 miles. How many more miles did she jog in the first w

eek?

2 answers:

shepuryov [24]3 years ago

8 0

9 3\8 is your answe i belive in fraction for at least

vivado [14]3 years ago

3 0

1.75 as a decimal
or 9 3/8 as a fraction

You might be interested in

Claire Reagan and Anthony deliver newspapers in the neighborhoods clear deliver 79 papers a day Reagan delivers 2490 papers a mo

Nata [24]

Answer:

90,747

Step-by-step explanation:

Clair delivery=79 per day

Total delivery per year=79×365 days

=28,835

Reagan delivery=2490 per month

Total delivery per year=2490×12 months

=29,880

Anthony delivery= 616 per week

Total delivery per year =616×52 weeks

=32,032

Total delivery altogether in a year=28,835+29,880+32,032

=90,747

4 0

3 years ago

Read 2 more answers

How do you simply 2x+8=-6

photoshop1234 [79]

To simplify <span>2x + 8 = -6, the easiest way is to manipulate the equation one step at a time:

</span>2x + 8 = <span>-6
</span>2x = <span>-14 (subtract 8 from both sides)
</span>x = -7 (divide both sides by 2)

3 0

3 years ago

Can someone help me ? i have no clue how to figure this out

Ad libitum [116K]

$\cos t (\sec t - \cos t) = \sin^2 t$

$\cos t (\dfrac{1}{\cos t} - \cos t) = \sin^2 t$

$\dfrac{\cos t}{\cos t} - \cos^2 t = \sin^2 t$

$1 - \cos^2 t = \sin^2 t$

Use the identity: $\sin^2 t + \cos^2 t = 1$ and solve for $\sin^2 t$ . You get: $\sin^2 t = 1 - \cos^2 t$

Do the substitution on the left side to get:

$\sin^2 t = \sin ^2 t$

5 0

2 years ago

Read 2 more answers

Angle Relationship

yaroslaw [1]

Answer:

B. 0.83

Step-by-step explanation:

I calculated it logically

7 0

2 years ago

Read 2 more answers

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 18 Southwest flights

r = number of success = at least 13 flights arrive late

p = probability of success which in our question is probability that

flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X $\geq$ 13)

P(X $\geq$ 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$

= 2.5196 $\times 10^{-6}$ .

7 0

3 years ago