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posledela
3 years ago
14

Please help me with these two problems i will fail if i dont turn in this assignment ​

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0

Answer:

4) Neither

Same y intercept means intersecting and intersecting is not an option

6) Perpedicular

A perpendicular line has a slope the reciprocal of each other like in this case

0.4= 2/5, 5/2=2.5

Oksanka [162]3 years ago
6 0

Answer:

Number 4 is neither, number 6 is perpendicular

Step-by-step explanation:

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For triangle ABC with A=103, B=24, a=16, find angle C
Ilya [14]

Answer:

given A=103° , B=24°

In triangle ABC,

A+B+C=180° [angle sum property of triangle]

103°+24°+C=180°

127°+C=180°

C=180°-127°

C=53°

hope it help u dear...

5 0
3 years ago
The matrix to solve
Maurinko [17]
This question is impossible to solve.

this is why:

if 4x-4=0
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I get these question quite a lot in my GCSEs.

you have to prove why they are fake.

4 0
3 years ago
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What is the resulting cross section if the cheesecake was sliced parallel to its points?
ad-work [718]

Answer:

Step-by-step explanation:

??What is parallel to a point?

If the cut is parallel to the cut-off point, the cross-section is a rectangle.

6 0
3 years ago
I need help with 6,7 pleaaseee
antiseptic1488 [7]
6. addition property of equality (because 7 was added to each side)

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5 0
3 years ago
Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is bet
valentina_108 [34]
Mean of the distribution = u = 222
Standard Deviation = s = 16

We have to find the probability that a value lies between 190 and 230.

First we need to convert these data values to z score.

z= \frac{x-u}{s}

For x = 190, 
z= \frac{190-222}{16}=-2

For x = 230
z= \frac{230-222}{16}=0.5

So, we have to find the percentage of values lying between z score of -2 and 0.5

P( -2 < z < 0.5) = P(0.5) - P(-2)

From standard z table, we can find and use these values.

P(-2 < x < 0.5 ) = 0.6915 - 0.0228 = 0.6687

Thus, there is 0.6887 probability that the data value will lie between 190 and 230 for the given distribution. 

5 0
3 years ago
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