The answer for this question is 79 :)
Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>
Suppose an infinity sequence defined by:

Then we have to calculate the following limit:

If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:

Hence the limit is:

Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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I got:
-2(2f-3g)
explanation:
used communicative property
So, values of x are: 
Step-by-step explanation:
We need to find the square root of 5x^2 = 300
Writing in mathematical form:

Divide both sides by 5


Taking square root on both sides






So, values of x are: 
Keywords: Square root
Learn more about square root at:
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