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PilotLPTM [1.2K]
2 years ago
15

John has saved $150 and

Mathematics
2 answers:
Vanyuwa [196]2 years ago
5 0

Answer:

10 weeks

Step-by-step explanation:

Total difference in money = $150 - $0

     = $150

Difference per week = $25 - $10

    = $15

divide 150 by 15 (150/15)

 = 10

Elden [556K]2 years ago
3 0

First equation:

y=10x+150

y=25x

10x+150=25x

15x=150

x=10

so, 10 weeks

EDIT:

how many dollars dey save? dunno

jkkkkk

For John

150+10(10)=

150+100=

250

For Erin

They both equal

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3 0
3 years ago
Two lamps marked 100 W - 110 V and 100 W - 220 V are connected i
ELEN [110]
<h2>Answer:</h2>

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

<h2>Step-by-step explanation:</h2>

Given:

<em>First lamp rating</em>

Power (P) = 100W

Voltage (V) = 110V

<em>Second lamp rating</em>

Power (P) = 100W

Voltage (V) = 220V

<em>Source</em>

Voltage = 220V

i. <u>Get the resistance of each lamp</u>.

Remember that power (P) of each of the lamps is given by the quotient of the square of their voltage ratings (V) and their resistances (R). i.e

P = \frac{V^2}{R}

<em>Make R subject of the formula</em>

⇒ R = \frac{V^2}{P}             ------------------(i)

<em />

<em>For first lamp, let the resistance be R₁. Now substitute R = R₁, V = 110V and P = 100W into equation (i)</em>

R₁ = \frac{110^2}{100}

R₁ = 121Ω

<em />

<em>For second lamp, let the resistance be R₂. Now substitute R = R₂, V = 220V and P = 100W into equation (i)</em>

R₂ = \frac{220^2}{100}

R₂ = 484Ω

<em />

<em />

ii.<u> Get the equivalent resistance of the resistances of the lamps.</u>

Since the lamps are connected in series, their equivalent resistance (R) is the sum of their individual resistances. i.e

R = R₁ + R₂

R  = 121 + 484

R = 605Ω

iii. <u>Get the current flowing through each of the lamps. </u>

Since the lamps are connected in series, then the same current flows through them. This current (I) is produced by the source voltage (V = 220V) of the line and their equivalent resistance (R = 605Ω). i.e

V = IR [From Ohm's law]

I = \frac{V}{R}

I = \frac{220}{605}

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iv. <u>Get the power consumed by each lamp.</u>

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P = I²R

Where;

I = current flowing through the lamp

R = resistance of the lamp.

<em>For the first lamp, power consumed is given by;</em>

P = I²R           [Where I = 0.36 and R = 121Ω]

P = (0.36)² x 121

P = 15.68W

<em>For the second lamp, power consumed is given by;</em>

P = I²R           [Where I = 0.36 and R = 484Ω]

P = (0.36)² x 484

P = 62.73W

Therefore;

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

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2 years ago
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