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geniusboy [140]
4 years ago
11

Byron wants to use Quick Parts to insert reusable content into a company Word document. Where will he access this option? Design

tab Insert tab Home tab Review tab

Computers and Technology
2 answers:
Klio2033 [76]4 years ago
8 0

Answer:

The correct answer is the option B: Insert Tab.

Explanation:

First of all, the feature of <em>Quick Parts</em> inside Microsoft's Word Office introduced in 2007 allows the user to create a library of content that the person commonly uses and then permits him to use that content everytime he needs instead of creating it again, therefore the content stays permanent.

Secondly, if the person wants to use this feature then he needs to first press Insert Tab in the Word's menu tool and then go the part of text group, in there the person will find the Quick Parts feature in the highest icon in the middle of the text group. Byron will find this feature very usefull due to the fact that <em>it will allow him to create, store and reuse the content he wants everytime he needs</em> into a company Word document.

storchak [24]4 years ago
7 0

Answer:

Insert tab

Explanation:

To use <em>Quick Parts</em>, first go to Insert tab then text group. The icon of <em>Quick Parts</em> is there in the attached picture.You can use the <em>Quick Part Gallery</em> to create, store, and reuse pieces of content, including <em>AutoText</em>, document properties (such as title and author), and fields. These reusable blocks of content are also called <u><em>building blocks</em></u>. <em>AutoText</em> is a common type of building block that stores text and graphics. You can use the <em>Building Blocks Organizer</em> to find or edit a building block

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Which type of app is the best choice when it is critical to be able to use the device's features but performance is not critical
lisov135 [29]

Answer:

Hybrid.

Explanation:

A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer on how to perform a specific task and solve a particular problem.

A software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications. There are seven (7) main stages in the creation of a software and these are; planning, analysis, design, development (coding), testing, implementation and execution, and maintenance.

Some of the models used in the software development life cycle (SDLC) are;

I. A waterfall model: it can be defined as a process which involves sequentially breaking the software development into linear phases. Thus, the development phase takes a downward flow like a waterfall and as such each phase must be completed before starting another without any overlap in the process.

II. An incremental model: it refers to the process in which the requirements or criteria of the software development is divided into many standalone modules until the program is completed.

III. A spiral model: it can be defined as an evolutionary SDLC that is risk-driven in nature and typically comprises of both an iterative and a waterfall model. Spiral model of SDLC consist of these phases; planning, risk analysis, engineering and evaluation.

Basically, softwares are categorized into three (3) main categories based on the development platform and these are;

a. Web application.

b. Native application.

c. Hybrid application.

A hybrid application is a type of software application that is designed based on the combination of the elements of both web applications and native applications.

Typically, a hybrid application is a web application that is developed in a native application shell, using a standardized web programming language such as CSS, JavaScript, and HTML.

Generally, a hybrid application avails a programmer the opportunity to write a code for a mobile application once while accommodating or being compatible with multiple app platforms such as Android, Windows, iOS, etc.

Hence, a hybrid application is the best choice of an application when it's critical for the end users to be able to use the features associated with a device such as a mobile phone but performance isn't critical.

4 0
3 years ago
1. Implement a method factorial(int n), that takes a number (int) and returns its factorial. Factorial of an integer is the prod
marysya [2.9K]

Answer:

import java.io.*;

import java.util.*;

public class Main

{

public static int factorial(int n){

if (n == 0)

return 1;    

else

return(n * factorial(n-1)); //recursively calling factorial function

}

public static void fibbonaci(int n)

{

if(n>0)

{

c=a+b; //next term in series

a=b;

b=c;

System.out.print(" "+c);    

fibbonaci(n-1); //recursively calling fibbonaci function

}

}

static int a=0,b=1,c;

  public static void main(String[] args) {

  int list_num,fact;

      List<Integer> num=Arrays.asList(1,3,5,7,9); //arraylist with 1,3,5,7,9

      for(Integer i:num) //for-each loop

      {    

      a=0;

      b=1;

      list_num=i.intValue();

      System.out.println("Fibbonaci series for "+list_num);

      System.out.print(a+" "+b);

      fibbonaci(list_num-2); //calling fibbonaci for values in list

      fact=factorial(list_num); //calling factorial for values in list

      System.out.println();

      System.out.println("Factorial for "+list_num+" is "+fact);

      System.out.println();

     

      }

  }

}

6 0
4 years ago
Suppose you have a 16-bit machine with a page size of 16B. Assume that any unsigned 16-bit integer can be a memory address. Also
irinina [24]

Answer:

2^11

Explanation:

Physical Memory Size = 32 KB = 32 x 2^10 B

Virtual Address space = 216 B

Page size is always equal to frame size.

Page size = 16 B. Therefore, Frame size = 16 B

If there is a restriction, the number of bits is calculated like this:  

number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]

where

physical memory size = 32KB  which is the restriction

n bit machine = frame size = 16

Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11

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3 years ago
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