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STALIN [3.7K]
1 year ago
6

write a program which prompts the user for a celsius temperature, convert the temperature to fahrenheit, and print out the conve

rted temperature.
Computers and Technology
1 answer:
JulsSmile [24]1 year ago
6 0

print("——OR——") Input ("Temperature value in degree Celsius:"), celsius 2 = float) Celsius 2 = (Fahrenheit 2 * 9/5) + 32; print the result.

The user's input is taken. Enter the temperature in celsius by typing it into the input box. Fahrenheit is equivalent to (celsius multiplied by 1.8) + 32 print(str(celsius)+ "A degree in Celsius is equal to a " + str(fahrenheit)+ " degree in Fahrenheit. The change from C to F is therefore 100/180, or 5/9. It is 180/100 or 9/5 from F to C. As a result, the conversion yields °F = °C (9/5) + 32. As a result, the equation for changing from the Celsius to Fahrenheit scale becomes °F = °C (9/5) + 32. To convert from degrees Fahrenheit to degrees Celsius, do the inverse calculation: subtract 30 from the degrees Fahrenheit reading, then multiply the result by two to obtain the degrees Celsius reading.

Learn more about conversion here-

brainly.com/question/13163755

#SPJ4

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Write a statement to declare a variable x with data type int and initialise with the value 10​
nexus9112 [7]

Answer:

int x = 10;

Explanation:

This would work in many languages (C/C++/C#/Java).

6 0
2 years ago
Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0
trasher [3.6K]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // variables

   char cust_t;

   int no_gallon;

   double cost=0;

   cout<<"Enter the type of customer(B for business or R for residential):";

   // read the type of customer

   cin>>cust_t;

   // if type is business

   if(cust_t=='b'||cust_t=='B')

   {

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.006;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {

           // if number of gallons is greater than 8000

           // calculate cost

           cost=(8000*0.006)+((no_gallon-8000)*0.008);

           cout<<"total cost is: $"<<cost<<endl;

           

       }

       

   }

   

   // if customer type is residential

   else if(cust_t=='r'||cust_t=='R')

        {

           

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.007;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {// if number of gallons is greater than 8000

       // calculate cost

           cost=(8000*0.005)+((no_gallon-8000)*0.007);

           cout<<"total cost is: $"<<cost<<endl;      

       }        

   }

return 0;

}

Explanation:

Ask user to enter the type of customer and assign it to variable "cust_t". If the customer type is business then read the number of gallons from user and assign it to variable "no_gallon". Then calculate cost of gallons, if  gallons are less or equal to 800 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and  for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 8000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter the type of customer(B for business or R for residential):b                                                                                            

please enter the number of gallons:9000                                                                                                                      

total cost is: $56  

4 0
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How many rows appear in a truth table for the compound proposition: \[(p \leftrightarrow q) \oplus (\neg p \leftrightarrow \neg
AURORKA [14]
Let me re-write the proposition:

p↔q⊕(¬p↔¬r)∧¬q.

Generally, the number of rows in a truth table depends on the number of Variables. Here we have 3 Variables: p,q and r. Each of them can have either the value of 1 or 0, which gives us 2*2*2 possibilities, or 2³, that is 8 possibilities and 8 rows:

p=0, q=0, r=0
p=0, q=0, r=1
p=0, q=1, r=0
p=0, q=1, r=1
p=1, q=0, r=0
p=1, q=0, r=1
p=1, q=1, r=0
p=1, q=1, r=1







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Who watched Unus Annus??? (If you did what was your favorite part?​
quester [9]

This video was completeley unedited was a banger, and so was the vid where they made robot amy. that was hilarious.

But since it is now Post Mortem all say here is...

Unas Annus. Memento Mori.

It sure was fun.

3 0
3 years ago
The computers in the administrative offices of the four schools throughout the district are networked to enable employees to acc
muminat
These computers in administrative offices or schools throughout the district that are networked to each other has the type of network most likely used by the workers is LAN network. Usually LAN networks are used in small offices or rooms.
3 0
3 years ago
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