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Ksenya-84 [330]
2 years ago
7

Which of the following shows the factors of 6x^2 - 3x - 18?

Mathematics
1 answer:
Inessa05 [86]2 years ago
5 0
(x-2)(2x+3)
not sure if this is what youre looking for though!
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Which statement is true about the given info
Anettt [7]

Answer: the one you have selected is correct.

ACE = 90

6 0
3 years ago
Read 2 more answers
( 5x + 685 ) + ( 12x - 106 ) = 2500
uysha [10]

Answer:

            x  = 113

Step-by-step explanation:

( 5x + 685 ) + ( 12x - 106 ) = 2500                                          ( 685 - 106 =   579)

                       17x  +  579 = 2500

                             17x        = 2500 - 579

                                    17x =     1921

                                       x = 1921 / 17

                                      x  = 113

3 0
3 years ago
Solve equation <br> -143 = 1+8(3 – 3b)
rodikova [14]

Answer:

b = 7

Step-by-step explanation:

-144 = 8(3-3b)

-18 = 3-3b

-21 = -3b

b = 7

4 0
3 years ago
Read 2 more answers
Give an example of a point that is the same distance from (3, 0) as it is from (7, 0). Find lots of examples. Describe the confi
Artist 52 [7]

Supposse that the distance from the point (x,y) to the point (3,0) is equal to the distance from  (x,y) to the point (7,0). Then, by the formula of the distnace we must have

\sqrt{(x-3)^2 + (y-0)^2}=\sqrt{(x-7)^2 + (y-0)^2}

cancel the square root and the (y-0)^2's, and then expand the parenthesis to obtain

x^2 - 6x + 9 = x^2 - 14x + 49

then, simplifying we obtain

8x = 40

therfore we must have

x=5

this means that the points satisfying the propertie must have first component equal to 5. So we can give a lot of examples of such points: (5,0), (5,7),(5,1/2), (5,-10),.... The set of this points give us a straight line and the points (3,0) and (7,0) are symmetric with respect to this line.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=solve%20for%20%22m%22%20t%3D%5Cfrac%7Bms%7D%7Bm%2Bn%7D" id="TexFormula1" title="solve for &quo
dalvyx [7]

Answer:

\boxed{\sf \ \ \ m = -\dfrac{tn}{t-s} \ \ \ }

Step-by-step explanation:

Hello,

let s assume that m+n is different from 0

we have this equation and we need to find m as a function of t, s, and n

t=\dfrac{ms}{m+n}

<=>

(m+n)*t=ms\\\\ tm+tn=sm\\ (t-s)m = -tn\\ m = -\dfrac{tn}{t-s}

for t-s different from 0, so t different from s

hope this helps

4 0
3 years ago
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