Question

100 random samples were taken from a large population. A particular numerical characteristic of sampled items was measured. The results of the measurements were as follows. 45 measurements were between 85.9 and 90.0 90.1 was observed once 90.2 was observed three times 90.3 was observed twice 90.4 was observed four times 45 measurements were between 90.5 and 95.8 The smallest value was 85.9 and the largest value was 95.8. The sum of all 100 measurements was 9117.0. Except those noted, no measurements occurred more than twice. What is the mean of the measurements?

Answer 1

Answer:

The mean of the measurements is 91.17.

Step-by-step explanation:

The mean is the sum of all measurements divided by the number of measurements.

For this problem, we have that:

The sum of all 100 measurements was 9117.0.

So, the sum of all measurements is 9117.

The number of measurements is 100.

So:

$M = \frac{9117}{100} = 91.17$

The mean of the measurements is 91.17.