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GaryK [48]
3 years ago
12

a counter top is in the shape of a trapizoid . the lengths of the base is 70 1/2 and 65 1/2 inches long. the area of the counter

top is 1,224 square inches . write and solve an equation to find the height of the countertop.

Mathematics
1 answer:
Grace [21]3 years ago
4 0
I attached a photo of the work below :-) 

Area of a trapezoid= [(a+b)÷2]h
1,224 in²= [(65.5 in+70.5in)÷2]h
1,224in²= (136÷2)h
1,224 in²= 68h
(1,224 in²÷68)= 68h÷68 (elimination)
h= 18 inches

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Step-by-step explanation:

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It is found that on average, 9% of the population recycles its garbage. Under this assumption, if a random sample of 120 househo
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Complete Question

It is found that on average, 9% of the population recycles its garbage. Under this assumption, if a random sample of 120 households in Iowa City is taken, would you be surprised to find that fewer than 3% of households in the sample recycle their garbage? Use the fact that p-hat has an approximately normal distribution.

Group of answer choices

A I would not be surprised because there are lots of lazy students in Iowa City.

B I would not be surprised because 3% is not that far away from 9%.

C I would be surprised because Iowa City is a very clean community which means lots of people recycle their garbage.

D I would be surprised because if the 9% average is true, the chance of a sample proportion being less than 3% is very small (only 1%). Who cares? It's only garbage!

Answer:

The correct option is D

Step-by-step explanation:

From the question we are told that

    The sample size is  n  = 120

    The  mean of the proportion is  p =  0.09

   

Generally the standard deviation is mathematically represented as

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=>   \sigma  =  \sqrt{\frac{0.09(1-0.09)}{120 } }

=>   \sigma  = 0.02612

Generally the chance that fewer than 3%   of households in the sample recycle their garbage is mathematically represented as

    P(X < 0.03) =  P( \frac{X - p}{\sigma}  <  \frac{0.03 -0.09}{0.02612} )

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From the z-table  

     P( Z  < -2.297 ) = 0.01

=> [tex]P(X < 0.03) = 0.01/tex]

=>   [tex]P(X < 0.03) = 1\% /tex]

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