Answer:
False
Explanation:
BugTraq is a high volume, full disclosure mailing list for the detailed discussion and announcement of computer security vulnerabilities, not US-CERT
Answer:
The method definition to this question can be given as:
Method definition:
double max(double x, double y) //define method with double parameter
{
if (x>=y) //check condition.
return x; //return value
else
return y; //return value
}
double max(int x, int y) //define method with integer parameter
{
if (x>=y) //check condition
return x; //return value
else
return y; //return value
}
double max(char x, char y) //define method with char parameter
{
if (x>=y) //check condition
return x; //return value
else
return y; //return value
}
Explanation:
The above method definition can be described as below:
- In the first method definition first, we define a method that is "max()". In this method we pass two variables as a parameter that is "x and y" and the datatype of this is double. Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
- In the second method definition, we define a method that is same as the first method name but in this method, we pass two integer variable that is "x and y". Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
- In the third method definition, we define a method that is same as the first and second method name but in this method, we pass two char variable that is "x and y". Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
An effective team leader shows great skills in every area, shows great support and respect to his teammates and is very easy to get along with.
import java.util.Scanner;
public class JavaApplication42 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int count = 0;
System.out.println("Enter an integer between 0 and 100");
int num = scan.nextInt();
if (num <= 0 || num >= 100){
System.out.println("error");
}
else{
while(num <= 100){
if (count == 20){
System.out.println("");
count = 0;
}
else{
System.out.print(num+" ");
count++;
num++;
}
}
}
}
}
I hope this helps!
