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Natalka [10]
3 years ago
10

a bank charges a fee on savings accounts that are inactive for an extended period time. the equation y =7500 (0.97)x represents

the value of y, of one account that was left inactive for a period of x years. what is the y-intercept of the equation and what dose it represent?
Mathematics
2 answers:
Leona [35]3 years ago
7 0

Answer: The y intercept = (0,7500)

It represents the original amount of money in the account  before left inactive. = $7,500

Step-by-step explanation:

Given: A bank charges a fee on savings accounts that are inactive for an extended period time.

The equation y =7500(0.97)^x represents the value of y, of one account that was left inactive for a period of x years.

To find the y intercept , put x=0 in the equation, we get

y=7500(0.97)^0=7500

Hence, the y intercept of the given equation = (0,7500)

It represents the amount of money in the account that was left inactive for a period of 0 years.

i.e that is the y intercept represents the original amount of money in the account before left inactive = $7,500

umka2103 [35]3 years ago
4 0
I assume the function is y =7500 (0.97)^x. The y-intercept is 7500 and it represents when the account is still active or have been inactive for 0 years.
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L^{-1}[\dfrac{e^{-3s}}{s+1}] = \left \{ {{f(t-3) \ \ \ t>3} \atop {0 \ \ \ \ \ \  \ \  \ t

L^{-1}[\dfrac{e^{-3s}}{s+1}] = \left \{ {{e^{(-t-3)} \ \ \ t>3} \atop {0 \ \ \ \ \ \  \ \  \ t

= e^{-t-3} \left \{ {{1 \ \ \ \ \  t>3} \atop {0 \ \ \ \ \  t

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