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saul85 [17]
3 years ago
14

The actual length of c in the triangle shown is 15 cm.

Mathematics
2 answers:
earnstyle [38]3 years ago
5 0

Answer:

B

hope this helped

Strike441 [17]3 years ago
4 0
The answer is B. Hope this helps!
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Which relation is a function of x?
stiv31 [10]

Answer:

x3

Step-by-step explanation:

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3 years ago
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What is the third term in the binomial expansion of (3x y3)4? 54x2y3 18x2y3 18x2y6 54x2y6.
hjlf

From the simplified form of the expression, the third term on expansion is 54x^2y^6

Given the expression (3x + y^3)^4

  • For binomial expansion, the power of 3x will be decreasing while y^3 will be increasing.

On expansion, the resulting expression will be:

  • =(3x + y^3)^4\\=(3x)^4(y^3)^0 + 4 (3x)^3(y^3)^1 + 6(3x)^2(y^3)^2 + 4(3x)^1(y^3)^3 + (3x)^0(y^3)^4\\

Simplify the result to have:

  • =81x^4+81x^3y^3+54x^2y^6+12xy^9+y^{12}

From the simplified form of the expression, the third term on expansion is 54x^2y^6

Learn more on binomial expansion here: brainly.com/question/13800206

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2 years ago
Liquefied natural gas makes ________ natural gas easier.
bija089 [108]
Your answer is C. Transporting

Hope I helped you today : )
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3 years ago
What transformations are used to get G’ , H’ , I’.
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Reflection on point H
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How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

f(x)=-4x^5-8x^3+12x

And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

Firstly, we can divide everything by -4:

0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

Solving for each case:

x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

4 0
2 years ago
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