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2 years ago

The actual length of c in the triangle shown is 15 cm.

Mathematics

2 answers:

earnstyle [38]2 years ago

5 0

Answer:

hope this helped

Strike441 [17]2 years ago

4 0

The answer is B. Hope this helps!

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Karl is building a rectangular garden bed. The length is 6 feet. She has 20 feet of boards to make the sides. Write and solve an

natali 33 [55]

Answer:

The width of the garden bed must be less than or equal to 4 feet.

$w\leq4$

Explanation:

Given that;

She has 20 feet of boards to make the sides.

The perimeter of the garden bed must not be more than 20 feet

$\begin{gathered} P=2l+2w\leq20 \\ 2l+2w\leq20 \end{gathered}$

Given;

The length is 6 feet;

$l=6$

To get the inequality for the width w, let us substitute the value of the length into the inequality above and simplify;

$\begin{gathered} 2l+2w\leq20 \\ 2(6)+2w\leq20 \\ 12+2w\leq20 \\ 2w\leq20-12 \\ 2w\leq8 \\ \frac{2w}{2}\leq\frac{8}{2} \\ w\leq4 \end{gathered}$

Therefore, the width of the garden bed must be less than or equal to 4 feet.

$w\leq4$

8 0

11 months ago

A radio station is giving away a $100 bill to every 30th caller and movie tickets to every 40th caller. Which call will be the f

Ymorist [56]

Answer:

120th caller

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

$100 bill = 30th caller

Movie tickets = 40th caller

So, to find out first to win both prizes, we will use LCM method,

LCM of 30 and 40 = 10 | 30 , 40

| 3 , 4

LCM of 30 and 40 = 10 × 3 × 4 = 120

Hence, 120th caller will be the first to win both prizes.

3 0

3 years ago

Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h

Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

$T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182$

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

$T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148$

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

$T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378$

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

$T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899$

So 2899 possible ways.

4 0

2 years ago

Graph Photo attahed

BabaBlast [244]

North divided by Total (Total of North, South, Central, East, and West)

North = 1

South = 4

Central = 2

East = 3

West = 2

North ÷ Total

1 ÷ (1 + 4 + 2 + 3 + 2 )

1 ÷ (12)

= $\frac{1}{12}$

Answer: B

6 0

3 years ago

Find the value of y.

sveticcg [70]

Hello,

it's an equilateral triangle, all sides and all angles are the same.

so they are all 4 cm sides.

4 = 2y + 6

-2y = 6 - 4

-2y = 2

y = 2 : 2

y = 1 or -1

5 0

3 years ago